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Makovka662 [10]
3 years ago
15

Gnb technologies manufactures lead-acid batteries, and enlists ups for assistance with its supply chain. ups also helps the comp

any to obtain used products that are then recycled, which has resulted in reclaiming 90% of the lead from gnb’s batteries. this is an example of
Physics
1 answer:
Elza [17]3 years ago
4 0
The company's method used in its marketing strategy as what is described in the description would be reverse logistics. In addition, a reverse logistics technique mainly involves re-using the company's products produced for the reason of properly disposing in, and could be used as another resource for future productions.
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What will a spring scale read for the weight of a 57.0-kg woman in an elevator that moves upward with constant speed of 5.0 m/s
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The spring scale will read 559 Newton's or 125.7 pounds.
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3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
3 years ago
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In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
3 years ago
When a piece of copper is taken to the moon , a change will be observed in it's ?​
SpyIntel [72]
Weight. Because there is less gravity on the moon.
3 0
2 years ago
If the box is a distance 1.81 m from the rear of the truck when the truck starts, how much time elapses before the box falls off
alexira [117]
If the box is a distance 1.81 m from the rear of the truck when the truck starts,<span> ... Force of Friction = mu_s * Normal Force( </span>M<span> * G) ... The </span>box starts<span> moving! ... Now that the </span>box<span> is moving, the bed of the </span>truck<span> pulls at it with 17.4 ... out how </span>long<span> it will take the </span>box<span> to reach the back of the </span>truck<span>. ... T^2 = 2 * </span>1.81<span> / .64</span>
4 0
3 years ago
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