<h2>
Height of cliff is 66.43 meter.</h2>
Explanation:
Consider the horizontal motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 1770 m/s
Acceleration, a = 0 m/s²
Displacement, s = 6520 m
Substituting
s = ut + 0.5 at²
6520 = 1770 x t + 0.5 x 0 xt²
t = 3.68 s
Time of flight of shell = 3.68 s.
Now consider the vertical motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3.68 s
Substituting
s = ut + 0.5 at²
s = 0 x 3.68 + 0.5 x 9.81 x 3.68²
s = 66.43 m
Height of cliff is 66.43 meter.
No. It’s moving at a constant speed (speed is not changing) in a straight line (same direction so velocity is not changing) so it is not accelerating. Acceleration only occurs if there’s a change in speed/velocity.
B, gossiping is unproessional
Answer:
Explanation:
let the charge is q. velocity, v = 24.7 m/s
magnetic force, F = 2.38 x 10^-4 N
Let the magnetic field is B.
Velocity, v' = 5.64 m/s
angle, θ = 21.2°
The force experienced by a charged particle placed in a magnetic field is given by
F = q x v x B x Sinθ
in first case
2.38 x 10^-4 = q x 24.7 x B x Sin 90 .... (1)
in second case
F = q x 5.64 x B x Sin 21.2° .... (2)
Divide equation (2) by equation (1), we get
F = 1.97 x 10^-5 N
