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Answer:
s = 20 m
Explanation:
given,
mass of the roller blader = 60 Kg
length = 10 m
inclines at = 30°
coefficient of friction = 0.25
using conservation of energy
u = 9.89 m/s
Using second law of motion
ma =μ mg
a = μ g
a = 0.25 x 9.8
a = 2.45 m/s²
Using third equation of motion ,
v² - u² = 2 a s
0² - 9.89² = 2 x 2.45 x s
s = 20 m
the distance moved before stopping is 20 m
Answer:
The velocity is
Henrietta is at distance from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is
The height of the window from the ground is
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is
=>
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Generally the time taken for the lunch to reach Henrietta is mathematically represented as
Here is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
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Generally the distance covered by Henrietta before catching her lunch is
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Generally the speed with which Bruce threw her lunch is mathematically represented as