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solniwko [45]
2 years ago
8

If the potential energy of a roller coaster is 60,000 J at the highest point, what is its kinetic energy at the lowest point?

Physics
1 answer:
VladimirAG [237]2 years ago
8 0

Answer:

60 000 J

Explanation:

The PE will be converted to KE entirely (if the lowest point is ground level)

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A 3.42 kg mass hanging vertically from a spring on the Earth (where g = 9.8 m/s2) undergoes simple oscillatory motion. If the sp
sineoko [7]

Answer:

Time period of oscillation on moon will be equal to 3.347 sec

Explanation:

We have given mass which is attached to the spring m = 3.42 kg

Spring constant K = 12 N/m

We have to find the period of oscillation

Period of oscillation is equal to T=2\pi \sqrt{\frac{m}{K}}, here m is mass and K is spring constant

So period of oscillation T=2\times 3.14\times \sqrt{\frac{3.42}{12}}

T=2\times 3.14\times 0.533=3.347sec

So time period of oscillation will be equal to 3.347 sec

As it is a spring mass system and from the relation we can see that time period is independent of g

So time period will be same on earth and moon

3 0
3 years ago
The Earth's magnetic field is generated in the Choose one: A. upper mantle. B. outer core. C. crust. D. inner core.
11111nata11111 [884]

Answer:

B

Explanation:

Magnetiic field of the earth is generated by the earths outer core

6 0
3 years ago
Which of these charges is experiencing the electric field with the largest magnitude? A 2C charge acted on by a 4 N electric for
Pavlova-9 [17]

Answer:

The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.

Explanation:

The formula for electric field is given as:

E = F/q

where,

E = Electric field

F = Electric Force

q = Charge Experiencing Force

Now, we apply this formula to all the cases given in question.

A) <u>A 2C charge acted on by a 4 N electric force</u>

F = 4 N

q = 2 C

Therefore,

E = 4 N/2 C = 2 N/C

B) <u>A 3 C charge acted on by a 5 N electric force</u>

F = 5 N

q = 3 C

Therefore,

E = 5 N/3 C = 1.67 N/C

C) <u>A 4 C charge acted on by a 6 N electric force</u>

F = 6 N

q = 4 C

Therefore,

E = 6 N/4 C = 1.5 N/C

D) <u>A 2 C charge acted on by a 6 N electric force</u>

F = 6 N

q = 2 C

Therefore,

E = 6 N/2 C = 3 N/C

E) <u>A 3 C charge acted on by a 3 N electric force</u>

F = 3 N

q = 3 C

Therefore,

E = 3 N/3 C = 1 N/C

F) <u>A 4 C charge acted on by a 2 N electric force</u>

F = 2 N

q = 4 C

Therefore,

E = 2 N/4 C = 0.5 N/C

The highest field is 3 N, which is found in part D.

<u>A 2 C charge acted on by a 6 N electric force</u>

3 0
3 years ago
Atoms of which elements form bonds without satisfying the octet rule?
leva [86]

Answer:

Helium and Hydrogen

Explanation:

8 0
3 years ago
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A physics book slides off a table at 1.25ms and hits the ground after 0.4s
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Answer:

Whats the question here?

7 0
3 years ago
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