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nlexa [21]
3 years ago
15

What is an independent or manipulated variable?

Physics
1 answer:
Paha777 [63]3 years ago
5 0

Is the variable you change, independent, I, something I change.

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Which of the following should you always use to protect yourself from hazardous moving parts of power tools and equipment
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A sound wave is an example of an electromagnetic wave in nature
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<span>A mechanical wave is a wave that is not capable of transmitting its energy through a vacuum. Mechanical waves require a medium in order to transport their energy from one location to another. A sound wave is an example of a mechanical wave.</span>
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3 years ago
Explain the relationship between lightning and storm clouds.
LuckyWell [14K]

Answer: Often lightning occurs between clouds or inside a cloud. But the lightning we usually care about most is the lightning that goes from clouds to ground.

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3 0
2 years ago
A Jeep accelerated at 2.2 m/s2 until after 18 seconds its displacement was 660 meters. Assuming the Jeep traveled in a straight
pogonyaev
Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660

Using the equation
r = ut +  \frac{1}{2} a {t}^{2}
With 'u' being the initial velocity we want, we get:
660 = 18u + 356.4
So:
18u = 303.6
So:
u = 16.8666
So the original/initial velocity was 16.8666 or 16.87 m/s

Hope this helped

5 0
3 years ago
A 100 kg box as showsn above is being pulled along the x axis by a student. the box slides across a rough surface, and its posit
Anit [1.1K]

Answer:

a) 2 m/s

b) i) K.E = 50 (1.5t^2 + 2) ^2\\

ii) F = 3tm

Explanation:

The function for distance is x = 0.5t ^3 + 2t

We know that:

Velocity = v= \frac{d}{dt} x

Acceleration = a= \frac{d}{dt}v

To find speed at time t = 0, we derivate the distance function:

x = 0.5 t^3 + 2t\\v= x' = 1.5t^2 + 2

Substitute t = 0 in velocity function:

v = 1.5t^2 + 2\\v(0) = 1.5 (0) + 2\\v(0) = 2

Velocity at t = 0 will be 2 m/s.

To find the function for Kinetic Energy of the box at any time, t.

Kinetic \ Energy = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times 100 \times (1.5t^2 + 2) ^2\\\\K.E = 50 (1.5t^2 + 2) ^2\\

We know that Force = mass \times acceleration

a = v'(t) = 1.5t^2 + 2\\a = 3t

F = m \times a\\F= m \times 3t\\F = 3tm

6 0
3 years ago
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