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nlexa [21]
3 years ago
15

What is an independent or manipulated variable?

Physics
1 answer:
Paha777 [63]3 years ago
5 0

Is the variable you change, independent, I, something I change.

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A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculat
valkas [14]

Answer:

a = 6.4 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])

m = mass of the block = 5 [kg]

a = acceleration [m/s²]

Now replacing:

40-8=5*a\\32 = 5*a\\a=6.4[m/s^{2} ]

Note: the sign of the friction force is negative since this force is acting against the movement of the block.

8 0
3 years ago
By 1949 Americans who lived within the range of a television stations in the country could watch TV, vastly changing the way tha
fredd [130]

Answer: Microwaves.

Explanation: First, we have a trivial answer, and that is the visible light, which is responsible to let the information on the tv to be seen by the user.

Now, TV technology was possible thanks to the microwaves, that are used because these can carry more energy than other types, and these microwaves needed a special technology because they couldn't be handled by the current technology at the time.

5 0
4 years ago
M1 is a spherical mass (25.0 kg) at the origin. M2 is also a spherical mass (10.6 kg) and is located on the x-axis at x = 94.8 m
Nata [24]

The point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

<h3>Position of the third mass</h3>

m1<------(x)------> m3 <-----------(94.8 m - x)-------->m2

a point, x, where m3 experiences a zero net gravitational force due to M1 and m2;

Force on m3 due to m1 = Force on m3 due to m2

Gm1m3/d² = Gm2m3/r²

m1/d² = m2/r²

where;

  • d is the distance between m1 and m3 = x
  • r is the distance between m3 and m2 = 94.8 - x

m1/(x²) = m2/(94.8 - x)²

m1(94.8 - x)² = m2x²

(94.8 - x)² = (m2/m1)x²

(94.8 - x)² = (10.6/25)x²

(94.8 - x)² = 0.424x²

(94.8 - x)² = (0.651)²x²

94.8 - x = 0.651x

94.8 = 1.651x

x = 94.8/1.651

x = 57.42 m

Thus, the point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.

Learn more about gravitational force here: brainly.com/question/72250

#SPJ1

8 0
2 years ago
300 watts of power is produced over 15 seconds. How much work was done transferring the power?
butalik [34]

Answer:

4500

Explanation:

Formula: power x time

300 x 15 = 4500

3 0
3 years ago
What are the results of habitat loss? choose the most likely outcome
zmey [24]
The Answer that makes the most sense is C.
5 0
3 years ago
Read 2 more answers
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