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ki77a [65]
4 years ago
11

Why do we see the color black?

Physics
1 answer:
Inessa [10]4 years ago
5 0
We see black colour in absence of light. Black colour absoorbs all the light, ( just opposite of white) and hence we do not see any colour. Black colour is also related to darkness.
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A hula hoop is rolling along the ground with a translational speed of 26 ft/s. It rolls up a hill that is 16 ft high. Determine
nikklg [1K]

Answer:12.8 ft/s

Explanation:

Given

Speed of hoop v=26\ ft/s

height of top h=16\ ft

Initial energy at bottom is

E_b=\frac{1}{2}mv^2+\frac{1}{2}I\omega ^2

Where m=mass of hoop

I=moment of inertia of hoop

\omega=angular velocity

for pure rolling v=\omega R

I=mR^2

E_b=\frac{1}{2}mv^2+\frac{1}{2}mR^2\times (\frac{v}{R})^2

E_b=mv^2=m(26)^2=676m

Energy required to reach at top

E_T=mgh=m\times 32.2\times 16

E_T=512.2m

Thus 512.2 m is converted energy is spent to raise the potential energy of hoop and remaining is in the form of kinetic and rotational energy

\Delta E=676m-512.2m=163.8m

Therefore

163.8 m=mv^2

v=\sqrt{163.8}

v=12.798\approx 12.8\ ft/s

7 0
3 years ago
A 45-gram object that has a volume of 9 mL has a density of
Elan Coil [88]
The answer : a. 5 g/mL
7 0
4 years ago
The fundamental force that is weak, long ranged and always relates the attraction of two masses is _____.
shutvik [7]

By definition this is the b) gravitational force.

5 0
3 years ago
Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf
Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = 1100^{\circ}C

Surface concentration of arsenic, C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}

Surface concentration below Silicon surface, C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}

D = 3.0\times 10^{- 14}\ cm^{2}/s

x = 1.2\mu m = 1.2\times 10^{- 4}\ cm

Initial concentration at t = 0, C_{o} = 0

Now, by using Flick's second eqn:

\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})

Thus by putting appropriate values:

\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})

0.997 = erf(\frac{364.4}{\sqrt{t}})              (1)

Now,

erf(z) = 0.997

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}

z = 2.12

Now, using eqn (1) and above value:

\frac{364.4}{\sqrt{t}} = 2.12

t = (\frac{364.4}{2.12})^{2} = 26700 s

t = \frac{26700}{3600} = 7.42\ h

7 0
3 years ago
From 0 seconds to 4 seconds is the acceleration positive or negative?
Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
4 years ago
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