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Fofino [41]
2 years ago
6

Add the following two vectors via the component method:

Physics
1 answer:
NeX [460]2 years ago
8 0

A quantity which have both magnitude and direction is know as vector quantity.

Resultant vector is 6.81 m south east.

Triangle law of vector addition is when two vectors are represented as two sides of the triangle with the order of magnitude and direction, then the third side of the triangle represents the magnitude and direction of the resultant vector.

Since, vector K is 3.0 m north and vector L is 8.6 m southeast

So, angle between vectors K and L is,

                                                                 90+45 = 135 degree

Resultant vector,  R=\sqrt{K^{2}+L^{2}=2*K*L*cosx  \\\\

                             R=\sqrt{9+73.96-36.49} \\\\R=\sqrt{46.47} \\\\R=6.81 m

So, Resultant vector R is 6.81 m with direction of southeast.

Learn more:

brainly.com/question/19791435

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Which is not an example of an external force acting on an object? (1 point)
GrogVix [38]

Answer:

A. a meteor traveling unhindered through space

Explanation:

7 0
3 years ago
A red train travelling at 72 km/h and a green train travelling at 144 km/h are headed toward each
abruzzese [7]

Answer:

  Collision will occur.

  Speed of red train when they collide = 0 m/s.

  Speed of green train when they collide = 10 m/s.

Explanation:

Speed of red train = 72 km/h = 20 m/s

Speed of green train = 144 km/h = 40 m/s.

Deceleration of trains = 1 m/s²

For red train:-

    Equation of motion v = u + at

              u = 20 m/s

              v = 0 m/s

              a = -1 m/s²

    Substituting

             0 = 20 - 1 x t

             t = 20 s.

    Equation of motion s = ut + 0.5at²

              u = 20 m/s

              t = 20 s

              a = -1 m/s²    

    Substituting

             s = 20 x 20 - 0.5 x 1 x 20² = 200 m

   So red train travel 200 m before coming to stop.

For green train:-

    Equation of motion v = u + at

              u = 40 m/s

              v = 0 m/s

              a = -1 m/s²

    Substituting

             0 = 40 - 1 x t

             t = 40 s.

    Equation of motion s = ut + 0.5at²

              u = 40 m/s

              t = 40 s

              a = -1 m/s²    

    Substituting

             s = 40 x 40 - 0.5 x 1 x 40² = 800 m

   So green train travel 800 m before coming to stop.

 Total distance traveled = 800 + 200 = 1000 m>950 m.

  So both trains collide.

  Distance traveled by green train when red train stops(t=20s)

     Equation of motion s = ut + 0.5at²

              u = 40 m/s

              t = 20 s

              a = -1 m/s²    

    Substituting

             s = 40 x 20 - 0.5 x 1 x 20² = 600 m

    Total distance after 20 s = 600 + 200 = 800 m< 950m . So they collide after red train stops.

  Speed of red train when they collide = 0 m/s.

  Distance traveled by green train when they collide = 950 - 200 = 750 m

  Equation of motion v² = u² + 2as

              u = 40 m/s

              s= 750 m

              a = -1 m/s²    

    Substituting  

              v² = 40² - 2 x 1 x 750 = 100

               v = 10 m/s

  Speed of green train when they collide = 10 m/s.

6 0
3 years ago
An airplane is flying overhead at a constant elevation of 3000ft. A man is viewing the plane from a position 4000ft from the bas
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Answer: The distance between the man and the plane increasing at a rate of 400ft/s

Explanation: Please see the attachments below

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