<span>Assume: neglect of the collar dimensions.
Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa
τ=(S*Q)/(I*b)=(40*〖10〗^3*π(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(π/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa
@ Point K:
Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa
Using Mohr Circle:
Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 )
Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
Answer:
Explanation:
Given the simultaneous equation,
3C+4D=5 .............. 1
2C+5D=2 ............... 2
Solving for the value of C and D using substitution method.
From equation 1;
3C = 5-4D
Divide both sides by 3
3C/3 = (5-4D)/3
C = (5-4D)/3 .... 3
From equation 2:
2C+5D=2
5D = 2-2C
Divide both sides by 5;
5D/5 = 2-2C/5
D = (2-2C)/5 ..... 4
Substitute equation 4 into 3;
C = 5-4{(2-2C)/5}/3
C = [5 - (8-8C/5)]/3
C = [25-(8-8C)/5]/3
C = (17+8C)/15
15C = 17+8C
15C-8C = 17
7C = 17
C = 17/7
Substitute C = 17/7 into equation 4 to get the value of D
D = (2-2(17/7))/5
D = (2-34/7)/5
D = 14-34/35
D = -20/35
D = -4/7
<em>Hence the value of C = 17/7, D = -4/7</em>
Mg magnesium becuase one period down and one group to the side
Based on the data provided, the thermal energies at the given time intervals are as follows:
- At time t = 0.0 secs; thermal energy = 0.0 J
- At time, t = 0.8 secs; thermal energy = 0.0 J
- At time, t = 2.0 secs; thermal energy = 3.9 J
- At time, t = 2.8 secs; thermal energy = 6.7 J
<h3>What is the law of conservation of energy?</h3>
The law of conservation of energy states that the total energy in an isolated system is conserved.
For a ball undergoing energy conversion between kinetic and potential energy, the sum of the energy remains constant.
Any reduction in total energy is due to conversion of some energy to thermal energy.
- Sum of energy: Kinetic + potential + thermal = 15.2 J
- Thermal energy = 15.2 - (PE + KE)
At time t = 0.0 secs
Thermal energy = 15.2 - (15.2 + 0.0)
Thermal energy = 0.0 J
At time, t = 0.8 secs
Thermal energy = 15.2 - (4.7 + 10.5)
Thermal energy = 0.0 J
At time, t = 2.0 secs
Thermal energy = 15.2 - (7.4 + 3.9)
Thermal energy = 3.9 J
At time, t = 2.8 secs
Thermal energy = 15.2 - (8.5 + 0.0)
Thermal energy = 6.7 J
Therefore, the thermal energies at the given time intervals are as follows:
- At time t = 0.0 secs; thermal energy = 0.0 J
- At time, t = 0.8 secs; thermal energy = 0.0 J
- At time, t = 2.0 secs; thermal energy = 3.9 J
- At time, t = 2.8 secs; thermal energy = 6.7 J
Learn more about conservation of energy at: brainly.com/question/166559
to get weight multiply Mass by 9.8
weight =9.8x15=147N
