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11111nata11111 [884]

2 years ago

9

You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the u

nderside of the balance pan. Removing the gum will improve the __________ of your measurements.

1 answer:

nadya68 [22]2 years ago

6 0

Answer:

accuracy

Explanation:

You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the underside of the balance pan. Removing the gum will improve the <u>accuracy</u> of your measurements.

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The diagram shows the electric field around two charged objects.

anyanavicka [17]

Here we have been given two charged body W and X.

We are asked to determine the nature of charge.

Before coming into conclusion, first we have to understand the electric field lines.

The electric field lines are pictorial representation of imaginary lines which are drawn to denote the electric field in a graphical way.

The electric field line starts from a positive charge and ends at a negative charge.It means for positive charges the electric field lines are outward and for negative charges the filed lines will be inward.

In the given diagram,the filed lines for W is towards W itself.The same is also in case of X.

Hence both the charges must be negative in nature.

Hence the correct answer to the question will be B i.e W negative and X: NEGATIVE.

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3 years ago

Read 2 more answers

MnS+HCl H 2 S+MnCl 2 Which set of coefficients would balance the equation?

rewona [7]

Answer:

1,2,1,1

Explanation:

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3 years ago

Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu

KiRa [710]

Answer:

(a) Determine the astronaut's orbital speed

The velocity of the astronaut is 1436m/s.

(b) Determine the period of the orbit.

The period of the orbit is 10413 seconds.

Explanation:

<em>(a) Determine the astronaut's orbital speed</em>

The orbital speed of astronaut can be found by means of the Universal law of gravity:

$F = G\frac{M \cdot m}{r^{2}}$ (1)

Then, replacing Newton's second law in equation 3 it is gotten:

$m\cdot a = G\frac{M \cdot m}{r^{2}}$ (2)

However, a is the centripetal acceleration since the astronaut describes a circular motion around the Moon:

$a = \frac{v^{2}}{r}$ (3)

Replacing equation 3 in equation 2 it is gotten:

$m\frac{v^{2}}{r} = G\frac{M \cdot m}{r^{2}}$

$m \cdot v^{2} = G \frac{M \cdot m}{r^{2}}r$

$m \cdot v^{2} = G \frac{M \cdot m}{r}$

$v^{2} = G \frac{M \cdot m}{rm}$

$v^{2} = G \frac{M}{r}$

$v = \sqrt{\frac{G M}{r}}$ (4)

Where v is the orbital speed, G is the gravitational constant, M is the mass of the Moon, and r is the orbital radius.

Notice that the orbital radius will be given by the sum of the radius of the Moon and the height of the astronaut above the surface.

But it is necessary to express the height of the astronaut above the surface in units of meters before it can be used.

$r = 680km \cdot \frac{1000m}{1km}$ ⇒ $680000m$

$r = 1.70x10^{6}m+680000m$

$r = 2380000m$

However it is neccesary to find the mass of Moon in order to use equation 4.

Then Newton's second law ( $F = ma$ ) will be replaced in equation (1):

$ma = G\frac{Mm}{r^{2}}$

Then, M will be isolated

$M = \frac{r^{2}a}{G}$ (5)

Where r is the orbital radius of the astronaut and a is the acceleration due to gravity.

$M = \frac{(2380000m)^{2}(0.867 m/s^{2})}{6.67x10^{-11}N.m^{2}/kg^{2}}$ (5)

$M = 7.36x10^{22}Kg$

$v = \sqrt{\frac{(6.67x10^{-11}N.m^{2}/kg^{2})(7.36x10^{22}Kg)}{2380000m}}$

$v = 1436m/s$

Hence, the velocity of the astronaut is 1436m/s.

<em>(b) Determine the period of the orbit. </em>

The period of the orbit can be determined by the next equation:

$v = \frac{2\pi r}{T}$ (6)

Where v is the orbital velocity, r is the orbital radius and T is the period of the orbit.

Then, T can be isolated from equation 6.

$T = \frac{2\pi r}{v}$ (7)

$T = \frac{2\pi (2380000m)}{1436m/s}$

$T = 10413s$

Hence, the period of the orbit is 10413 seconds.

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3 years ago

Describe how a change in resistance would affect the current in a circuit

Elena-2011 [213]

Resistance typically opposes flow of current.

When the Resistance is increased, the current would be reduced, but when the Resistance is reduced, the current would be increased in the circuit.

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3 years ago

Where is the planet moving faster?

algol [13]

Do you mean what planets moves the fastest?

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3 years ago