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Dafna1 [17]
3 years ago
15

An electric field of magnitude e is measured at a distance r from a point charge q. if the charge is doubled to 2q, and the elec

tric field is now measured at a distance of 2r from the charge, what is the value of the new electric field?
Physics
1 answer:
pav-90 [236]3 years ago
5 0
Electric field is proportional to the charge and inversely proportional to the square of distance:
E\propto\frac{Q}{r^{2}}
With charge 2q and distance 2r, the electric field is proportional to:
E_{q}\propto\frac{2q}{(2r)^{2}}=\frac{2q}{4r^{2}}=\frac{1}{2}\frac{q}{r^{2}}
The new electric field is half of that of the original measured field.
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