The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.
<h3>What is heat energy?</h3>
Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,
Given,
Mass of water = 456 gm
Specific heat capacity = 4.186 J / g K
Temperatutre change = 14.85 K
Substituting values above:
Therefore, 28.34 kJ of heat energy should be removed from the water.
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Answer: 16 atm
Explanation:
P1V1 = P2V2
P2 = P1V1/V2
=4 atm x 8.00 L/2.00L = 16 atm
Answer:
about 3
Explanation:
just did this for the points just being honiest
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+ + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:
PH= -㏒[H+]
= -㏒(4.81x10^-7) = 6.32
