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aliya0001 [1]
2 years ago
6

How many molecules are there in 122 grams of Cu(NO3)2?

Chemistry
1 answer:
ipn [44]2 years ago
6 0
Cu =63.5
2 times N =28.02
6 times O =96
96=63.5=28.02=127.07
122/127.07=.96 molecules
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What is the mass, in grams, of 7.20×1020 molecules of caffeine, c8h10n4o2?
pickupchik [31]
To determine the mass, you need to know the molecular weight of the c8h10n4o2 . The molecular weight of <span>c8h10n4o2 would be: 8*12 + 10*1 + 4*14 + 2*16= 194g/mol.
To convert the number of molecules into moles, you need to divide it with 6.02 * 10^23. The calculation of the mass of </span>c8h10n4o2 would be: 
(7.20×10^20 molecules)  /(6.02 * 10^23 molecule/mol)  * 194g/mol= 232 * 10^-3 grams= 0.232 grams
3 0
3 years ago
Read 2 more answers
How do scientific models help us teach students about systems?
kotegsom [21]

D)By increasing or decreasing the size of systems that are difficult to study we make it easier for students to see how they work and therefore make it easier for them to learn.

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Scientific models makes it easier to teach students about systems because their sizes can be adjusted and this makes it easier for students to see how they work.

A model is a simplification of the real work. It takes a part of the real world and studies it.

Models are highly desired in teaching and understanding very complex systems.

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4 0
2 years ago
A body of mass 5kg has momentum of 125kgm/s. find the velocity of the body in motion.
borishaifa [10]

Explanation:We have momemtum = mass X velocity

    p = mv

    OR, p/m = v

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8 0
3 years ago
Describe the number and type of each component of the molecule methane
Tasya [4]

Answer:

Methane is a chemical compound with the molecular formula CH4. It is the main component in natural gas. Methane is considered the simplest of alkanes, compounds that consist only of hydrogen (H) and carbon (C) elements. Methane is an odorless, colorless, tasteless gas that is lighter than air.

Explanation:

4 0
3 years ago
A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a
KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

  • Partial pressure of methane (pCH₄): 431 mmHg
  • Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

3 0
2 years ago
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