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Vitek1552 [10]
3 years ago
13

How many atoms are in 2.50 mol of hydrogen?

Chemistry
2 answers:
mash [69]3 years ago
6 0

Answer:

No. of atoms in 2.50 of hydrogen = 1.50\times 10^{24}\ atoms

Explanation:

Moles of Hydrogen = 2.50 mol

Number of atom = Moles × Avogardro's no.

Avogadro's no. = 6.02 \times 10^{23}atoms

Number of atom = Moles × Avogardro's no.

=2.50 \times 6.02 \times 10^{23}\\=1.50\times 10^{24}\ atoms

So, no. of atoms in 2.50 of hydrogen = 1.50\times 10^{24}\ atoms

Nimfa-mama [501]3 years ago
5 0
To do this, you must multiply the number of moles by the Avogadro's number, <span>6.0221409e+23

So, with 2.50 mol,
</span><span>
2.50 mol H * 6.02 * 10^23 atoms H / 1 mol H = 1.51 * 10^24 atoms H.

To make that statement clearer, in 2.50 mol of Hydrogen, there are 1.51x10^24 atomsH</span><span><span /></span>
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1. Which of the following nuclear equations is correctly balanced? (choices attached)
lawyer [7]

1. <em>Balancing nuclear equations </em>

Answer:

_{18}^{37}\text{Ar} + _{-1}^{0}\text{e} \rightarrow _{17}^{37}\text{Cl}

Explanation:

The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts</em> (the mass numbers) and the <em>subscripts</em> (the nuclear charges) <em>must balance</em>.

Mass numbers: 37 + 0 = 37; balanced.

Charges: 18 + 1 = 17; balanced

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C is <em>wron</em>g. Mass numbers not balanced. 254 + 4 ≠ 258 + 2(1).

D is <em>wron</em>g. Mass numbers not balanced. 14 + 4 ≠ 17 + 2.

===============

2. <em>Amount remaining </em>

Answer:

D. 5.25 g

Explanation:

The half-life of Th-234 (24 da) is the time it takes for half the Th to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.

We can construct a table as follows:  

  No. of                  Fraction       Amount  

<u>half-lives</u>   <u>t/(da</u>)  <u>remaining</u>  <u>remaining/g</u>  

      1             24            ½                21.0  

      2            48            ¼                10.5  

      3             72           ⅛                 5.25  

      4             96          ¹/₁₆                 2.62  

We see that 72 da is three half-lives, and the amount of Th-234 remaining is 5.25 g.  

===============

3.<em> Calculating the half-life </em>

Answer:

a. 2.6 min

Explanation:

The fraction of the original mass remaining is 1.0 g/4.0 g ≈ ¼.

We saw from the previous table that it takes two half-lives to decay to ¼ of the original amount.

2 half-lives = 5.2 min       Divide both sides by 2

  1 half-life = 5.2 min/2 = 2.6 min

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