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asambeis [7]
2 years ago
11

How many grams of KNO3 are required to prepare 0.250 L of 0.70 M solution?​

Chemistry
1 answer:
drek231 [11]2 years ago
4 0

Answer:

about 3

Explanation:

just did this for the points just being honiest

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12) Which model of the atom is thought to be true?
Oxana [17]

Answer:

B

Explanation:

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3 years ago
In one kind of nuclear reaction, two nuclei fuse, or join together, to form a larger nucleus. This kind of reaction happens only
Vladimir79 [104]
High pressures are necessary to create such reaction so that the particles will be able to overcome electrostatic repulsion. The particles that make up a particular atom are covered by shells of energy that react to different impulses like pressure. When particles are exposed to extreme environmental pressure it has the tendency to split its particles and undergo nuclear fusion successfully.
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3 years ago
Explain why an insoluble compound added to water is considered a nonelectrolyte.
DaniilM [7]

Explanation:

A non-electrolyte is defined as a solution which does not contain any ions and hence, it is unable to conduct electricity.

For example, when a non-polar substance like CCl_{4} is dissolved in water then it will not dissociate into ions.  

As electricity is the flow of ions or electrons. So, a non-electrolyte solution is not able to conduct electricity.

Similarly, a compound that is insoluble in water will not dissociate into ions. Hence, this type of solution will not be able to conduct electricity.

8 0
3 years ago
How many grams of O2 are needed to react with 18.2 g of NH3?
erastova [34]

Answer:

44 g oxygen are needed.

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g/ 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

                          4                 :                 5

                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.375 mol × 32 g/mol

Mass = 44 g

4 0
3 years ago
What part of the microscope is the letter k?
snow_tiger [21]

Answer:

if you are asking k then the round one is condenser

if not then its a stage clip

6 0
3 years ago
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