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asambeis [7]
2 years ago
11

How many grams of KNO3 are required to prepare 0.250 L of 0.70 M solution?​

Chemistry
1 answer:
drek231 [11]2 years ago
4 0

Answer:

about 3

Explanation:

just did this for the points just being honiest

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Which of the following statements provides the BEST explanation for the many chemical similarities between two elements in a Mai
rjkz [21]

Answer:

(b) Both have the same number of valence electrons.  

Step-by-step explanation:

We find the most striking chemical similarities between two Main Group elements when they are in the same Group of the Periodic Table.

Elements in the same Group have the same number of valence electrons.

(a) is <em>wrong</em>, because elements in the same group have <em>different masses</em>.

(c) is <em>wrong,</em> because atoms with the same number of protons belong to the s<em>ame element</em>.

(d) is wrong, because elements in the same Group must be in . <em>different Periods.</em>

7 0
3 years ago
Can you think of other solutions that might be<br> acidic?
bija089 [108]

Answer:

i think the answer is yess

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3 years ago
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The addictive power of nicotine is enhanced by which of the following chemicals?
ArbitrLikvidat [17]
The correct answer is A. Ammonia.
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3 years ago
Describe the function of each of the following types of neurons.
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B will be the one I think tbh
5 0
3 years ago
g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir
sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

7 0
3 years ago
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