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loris [4]
2 years ago
5

Define Gravitational Potential Energy.

Chemistry
1 answer:
Anna11 [10]2 years ago
6 0

Answer:

Gravitational energy or gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity. It is the potential energy associated with the gravitational field, which is released when the objects fall towards each other.

Explanation:

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Please help
inna [77]

From the calculation, the standard free energy of the system is -359kJ.

<h3>What is the standard free-energy?</h3>

The  standard free-energy is the energy present in the system. We have to first obtain the cell potential using the formula;

Ereduction - E oxidation = 0.96 V - 0.34 V = 0.62 V

Using the formula;

ΔG = -nFEcell

ΔG =-(6 * 96500 * 0.62)

ΔG =-359kJ

Learn more about free energy:brainly.com/question/15319033

#SPJ1

3 0
1 year ago
The atomic masses of the two stable isotopes of boron; boron-10 (natural abundance:19.78%) and boron-11 (natural abundance:80.22
iogann1982 [59]
(19.78 x 10) + (80.22 x 11) all of them divided by 100= 10.81 amu
5 0
3 years ago
What physical properties can be used to separate heterogeneous mixture's?
marysya [2.9K]
Evaporation, distillation, filtration and chromatography
Hope it help you, have a nice day
7 0
2 years ago
What is plasma and how /why does it form
Hunter-Best [27]

Answer:

I can answer 1 part Plasma is the fluid part of blood at least in bio(srry if it doesnt work)

Explanation:

7 0
3 years ago
What is the answers and pls show work if possible!!
taurus [48]

D = m / V


It even gives you the density of gold in the problem. Major hint. Once you know the volume (using V = m / D) then you can calculate the height (thickness) from the equation...


V = L x W x H

Volume = Length x Width x Height


start by converting 200.0 mg into grams

1000 mg = 1 g

200. mg x (1 g / 10^3 mg) = 0.200 g


V = m / D

V = 0.200 g / (19.32 g/cm^3)

V = 0.01035 cm^3


Convert 2.4 ft and 1 ft to cm

2.4 ft x (12 in / 1 ft) x (2.54 cm / 1 in) = 73.15 cm

1 ft = 30.48 cm


Compute the height (thickness)

V = LxWxH

H = V / LW = 0.01035 cm^3 / 73.15 cm / 30.48 cm

H = 4.64 x 10^-6 cm


Convert to nanometers

4.64 x 10^-6 cm x (1 m / 100 cm) x (10^9 nm / 1 m) = 46.4 nm


Knowing the atomic radius of gold, I might have asked my students for the minimum number of gold atoms in this thickness of gold. This would assume that the gold atoms are all in a row. This would give the minimum number of gold atoms.


Atomic radius gold = 174 pm

Diameter = 348 pm


46.4 nm x (1 m / 10^9 nm) x (10^12 pm / 1 m) x (1 Au atom / 248 pm) = 133 atoms of gold


4 0
3 years ago
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