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Nookie1986 [14]
2 years ago
12

Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound​

Chemistry
1 answer:
olga_2 [115]2 years ago
8 0

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

Correct me if I'm wrong tnx:<

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How does the size of the atoms relate to how reactive it is?
pishuonlain [190]

Answer: nucleus

Explanation: the bigger the nucleus there more reactive the atom is

5 0
3 years ago
Read 2 more answers
n-Butane (C4H10) is burned with stoichiometric amount of oxygen. Determine the mole fraction of carbon dioxide and water in the
Fudgin [204]

Answer:

See details below

Explanation:

The balanced reaction equation is given below:

2C_{4} H_{10} + 13O_{2} → 8CO_{2} + 10H_{2} O

Mole fraction of CO2 to H20

= 8/10 = \frac{4}{5}

Mole ratio of C4H10 to CO2 is 2:8 = 1:4

1 mole of n-butane - 38.12 g

4 moles - ?

= 152.48g fuel consumed.

8 0
3 years ago
An element is a mixture of two isotopes.one isotope has an atomic mass of 34.969 amu and an abundance of 64.88
skad [1K]

An element is a mixture of two isotopes. One isotope has an atomic mass of 34.969 amu and an abundance of 64.88%. The other isotope has an atomic mass 36.966 amu.


5 0
3 years ago
Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​
Inessa05 [86]

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

7 0
2 years ago
What information is need to calculate the percent composition of a compound?
Anestetic [448]

Answer:

Molecular formula

Explanation:

Molecular formula in the first place is required to understand which compound we have. We then should refer to the periodic table and find the molecular weight for each atom. Adding individual molecular weights together would yield the molar mass of a compound.

Then, dividing the total molar mass of a specific atom by the molar mass of a compound and converting into percentage will provide us with the percentage of that specific atom.

E. g., calculate the percent composition of water:

  • molecular formula is H_2O;
  • calculate its molar mass: [tex]M = 2M_H + M_O = 2\cdot 1.00784 g/mol + 16.00 g/mol = 18.016 g/mol;
  • find the percentage of hydrogen: [tex]\omega_H = \frac{2\cdot 1.00784 g/mol}{18.016 g/mol}\cdot 100 \% = 11.19 %;
  • find the percentage of oxygen: [tex]\omega_O = \frac{16.00 g/mol}{18.016 g/mol}\cdot 100 \% = 88.81 %.
8 0
3 years ago
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