Answer:
upper left
Explanation:
it is a trend on the periodic table. Ionization energy increases from left to right(->) I t also increases down to up
Answer:
0.42%
Explanation:
<em>∵ pH = - log[H⁺].</em>
2.72 = - log[H⁺]
∴ [H⁺] = 1.905 x 10⁻³.
<em>∵ [H⁺] = √Ka.C</em>
∴ [H⁺]² = Ka.C
∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.
<em>∵ Ka = α²C.</em>
Where, α is the degree of dissociation.
<em>∴ α = √(Ka/C) </em>= √(8.065 x 10⁻⁶/0.45) = <em>4.234 x 10⁻³.</em>
<em>∴ percentage ionization of the acid = α x 100</em> = (4.233 x 10⁻³)(100) = <em>0.4233% ≅ 0.42%.</em>
1.AIH3O3
2.Na2O4S
3.BrLi
4.KF
5.MgN2O6
6.Sr3N2
7.CaCO3
All numbers should be subscripts
Answer:
1.17 L
Explanation:
Step 1: Given data
- Initial volume (V₁): 1.50 L
- Initial pressure (P₁): 1.10 atm
- Initial temperature (T₁): 25 °C
- Final pressure (P₂): 1.50 atm
- Final temperature (T₂): 45 °C
Step 2: Convert the temperatures to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 25°C + 273.15 = 298 K
K = 45°C + 273.15 = 318 K
Step 3: Calculate the final volume of the neon gas
If we assume ideal behavior, we can calculate the final volume of the neon gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 1.10 atm × 1.50 L × 318 K / 298 K × 1.50 atm = 1.17 L
In Alpha decay two neutrons and protons are lost, so the mass decreases by four and the atomic number decreases by two.
Therefore the correct answer is B: Ra-224.