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zloy xaker [14]
2 years ago
9

The probability that a light bulb will have failed after 1000 hours of use is

Mathematics
1 answer:
son4ous [18]2 years ago
7 0

Answer:

.093

Step-by-step explanation:

do

1.00-0.07

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A putt putt course offers a deal that when you purchase 10 rounds of golf, you get 1 round for free. if you played a total of 35
natima [27]
35/11 = 3.18..... 

This means that out of 35 rounds only 3 of them were free because every 11 rounds 1 is free.

so 35-3=32

You purchased 32 rounds.

Please mark brainliest. This was kind of a confusing question at first.


5 0
3 years ago
Read 2 more answers
Factor this polynomial expression. x^2-16
V125BC [204]

Hi,

We know that:

a² -- b² = (a -- b)(a + b).

With a = x, and b = 4, we have:

x² -- 16 = x² -- 4² = (x -- 4)(x + 4).

As simple as that. Have you understood ?

Green eyes.

6 0
3 years ago
A baby gains 11 pounds in its first year of life. The baby gained 4 and one-fourth pounds during the first four months and 3 and
scoundrel [369]

Answer:

3.25

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
1.2+3x6= <br> 2.4(8-3)=<br> 3.7+8(3+2)= <br> 4. (6-5)+(8x10)=
Irina18 [472]

Answer:

1.2 + 3x6 = 19.2

2.4(8-3) = 11.25

3.7 + 8 (3 + 2) = 43.7

4(6 - 5) + (8 x 10) = 84

Hope this helps!

Have a great day

7 0
3 years ago
Read 2 more answers
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
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