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artcher [175]
2 years ago
9

30

Physics
1 answer:
pickupchik [31]2 years ago
4 0

Answer:

22m/s

Explanation:

lowest part on the graph (closest to x-axis)

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How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
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The answer is ....  C. 17,705.1 J
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A line of charge starts at x = +x0 and extends to positive infinity. The linear charge density is λ = λ0x0/x. Determine the elec
kari74 [83]

Explanation:

it is given that, the linear charge density of a charge, \lambda=\dfrac{\lambda_ox_o}{x}

Firstly, we can define the electric field for a small element and then integrate for the whole. The very small electric field is given by :

dE=\dfrac{k\ dq}{x^2}..........(1)

The linear charge density is given by :

\lambda=\dfrac{dq}{dx}

dq=\lambda.dx=\dfrac{\lambda_ox_o}{x}dx

Integrating equation (1) from x = x₀ to x = infinity

E=\int\limits^\infty_{x_o} {\dfrac{k\lambda_ox_o}{x^3}}.dx

E=-\dfrac{k\lambda_ox_o}{2}\dfrac{1}{x^2}|_{x_o}^\infty}

E=\dfrac{k\lambda_o}{2x_o}

Hence, this is the required solution.

5 0
3 years ago
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A red laser with a wavelength of 670 nm and a blue laser with a wavelength of 450 nm emit laser beams with the same light power.
tatyana61 [14]

E=hf C=wavelength*F

E=hC/wavelength

E=(6.626*10^-34)*(3.00*10^8)/670*10^-9

E=(6.626*10^-34)*(3.00*10^8)/450*10^-9

6 0
3 years ago
In 2h2so4, the number of hydrogen atoms is 1 2 4 8
pishuonlain [190]
C.) In this, number of Hydrogen atoms is 4
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In February 2004, scientists at Purdue University used a highly sensitive technique to measure the mass of a vaccinia virus (the
OlgaM077 [116]

Answer:

a)   m_v = m_s ((\frac{w_o}{w})² - 1) ,  b)  m_v = 1.07 10⁻¹⁴ g

Explanation:

a) The angular velocity of a simple harmonic motion is

           w² = k / m

where k is the spring constant and m is the mass of the oscillator

let's apply this expression to our case,

silicon only

         w₉² = \frac{K}{m_s}

         k = w₀² m_s

silicon with virus

         w² = \frac{k}{m_s + m_v}

          k = w² (m_v + m_s)

in the two expressions the constant k is the same and q as the one property of the silicon bar, let us equal

           w₀²  m_s = w² (m_v + m_s)

           m_v = (\frac{w_o}{w})²  m_s - m_s

           m_v = m_s ((\frac{w_o}{w})² - 1)

b) let's calculate

          m_v = 2.13 10⁻¹⁶ [(\frac{20.4}{2.85})² - 1)]

          m_v = 1.07 10⁻¹⁴ g

4 0
3 years ago
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