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Ivenika [448]
3 years ago
13

Newton's second law problem. The spring constant can be determined from the balance of forces in equilibrium. Suppose the spring

extends a distance LaTeX: \Delta Δ x when additional mass LaTeX: \Delta Δ m is added. Write down Newton's second law for this case and solve for k.[Answer: K=delta m g/delta x.] Make sure you understand how this formula was derived. If delta m=41 g and delta x=6cm,what is k?
Physics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

K =6.697 Kg/s²

Explanation:

Given:

delta m =41 g = 0.041 kg

delta x = 6cm = 0.06m

g = 9.8 m/s²

according to the given formula

K = delta m g /delta x

K = (0.041 kg × 9.8 m/s²) / 0.06m

K =6.697 Kg/s²

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A spherical mirror is polished on both sides. When the concave side is used as a mirror, the magnification is 4.4. What is the m
patriot [66]

Answer:

m = \frac{-4.4}{7.4}

Explanation:

magnification is the ratio of distance of image to distance of object

i.e. m = -\frac{d_i}{d_o}

d_i = -4.4 d_o

As per the lens equation,

\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}

We will calculate the focal length of the mirror

\frac{1}{yd_o} + \frac{1}{-4.4d_o} = \frac{1}{f} \\\frac{4.4 -1}{4.4} \frac{1}{d_o} =  \frac{1}{f}\\f = \frac{4.4}{3.4}  d_o

Now for convex mirror only the sign will change

Thus, focal length would be equal to

f = - \frac{4.4}{3.4} d_o

Plugging this value into lens equation, we get

\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} \\\frac{1}{d_o} + \frac{1}{d_i} = \frac{-3.4}{4.4} \frac{1}{d_o} \\\frac{7.4}{4.4} \frac{1}{d_o} = \frac{1}{d_i}\\\frac{d_i}{d_o} = \frac{4.4}{7.4} \\m =-  \frac{d_i}{d_o} \\\\m = - \frac{4.4}{7.4}

8 0
3 years ago
Sam heaves a 16lb shot straight upward, giving it a constant upward acceleration from rest of 35 m/s^2 for 64.0 cm. He releases
makvit [3.9K]

Answer:

6.69 m/s

4.483 m

1.42s

Explanation:

Given that:

Initial Velocity, u = 0

Final velocity, v =?

Acceleration, a = 35m/s²

1.) using the relation :

v² = u² + 2as

v² = 0 + 2(35) * 64*10^-2m

v² = 70 * 0.64

v = sqrt(44.8)

v = 6.693

v = 6.69 m/s

B.) height from the ground, h0 = 2.2

How high ball went , h:

Using :

v² = u² + 2as

Upward motion, g = - ve

0 = 6.69² + 2(-9.8)*(h - 2.2)

0= 6.69² - 19.6(h - 2.2)

44.7561 + 43.12 - 19.6h = 0

19.6h = 44.7561 - 43.12

h = 87.8761 / 19.6

h = 4.483 m

C.)

vt - 0.5gt² = h - h0

6.69t - 0.5(9.8)t²

6.69t - 4.9t² = 1.83 - 2.2

-4.9t² + 6.69t + 0.37 = 0

Using the quadratic equation solver :

Taking the positive root:

1.4185 = 1.42s

5 0
3 years ago
A 250 g beach ball rolls across the sand with a speed of 11.16 km/h. First convert units to kg and m/ then determine the momentu
yuradex [85]

Answer:

0.775 kg-m/s

Explanation:

Convert the units to the right unit forms necessary

250 g -> 0.25 kg

11.16 km/h -> 3.1 m/s

Now use the formula:

                         velocity

                   mass /  

momentum  /    /

       \           /    /

         \       /    /

          p = mv

p = 0.25 × 3.1 = 0.775 kg-m/s

Hope this helps you!

Bye!

6 0
3 years ago
A toy train is traveling along a circular track
Molodets [167]

Answer:

0.25 m

Explanation:

a = v² / r

4.0 m/s² = (1.0 m/s)² / r

r = 0.25 m

3 0
3 years ago
What is the direction of the force of an object moving in a circle?
Ivanshal [37]

Answer:

The answer is 45 degree angle

7 0
3 years ago
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