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Alex73 [517]
3 years ago
14

Answer fast , is si unit newton/meter square or pascal or both

Physics
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

Both

Explanation:

The S.I. unit of pressure is newton/meter square or pascal as both represent the same dimensional value.

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In an RL series circuit, an inductor of 3.54 H and a resistor of 7.76 Ω are connected to a 26.6 V battery. The switch of the cir
podryga [215]

Answer:

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So  current i=\frac{V}{R}=\frac{26.6}{7.76}=3.427Amp

Now energy stored in inductor E=\frac{1}{2}Li^2=\frac{1}{2}\times 3.54\times 3.427^2=20.797J

So energy stored in inductor will be 20.797 J

4 0
4 years ago
The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

P_x=rcos\theta

P_y=rsin\theta

where \thetais angle made by horizontal bar with x axis

Velocity at y=150 mm

150=300sin\theta

thus \theta =30^{\circ}

position ofP_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}

P_x=259.80 mm

P=259.80\hat{i}+150\hat{j}

Velocity at this instant

u_x=-rsin\theta =300\times sin30=-150 mm/s

u_y=rcos\theta =300\times cos30=259.80 mm/s

4 0
3 years ago
I need help on this question, please.
frez [133]

Answer:

|X| = 72 cm

Explanation:

We need to find the magnitude of vector X.

Vector Y = 21 cm

Vector Z = 75 cm

We know that, the magnitude of resultant vector is given by :

Z={X^2+Y^2} \\\\X^2=Z^2-Y^2\\\\X^2=(75)^2-(21)^2\\\\X=72\ cm

So, the value of magnitude of vector X is 72 cm

4 0
3 years ago
3 A picture is supported by two vertical strings; if the weighi
andrezito [222]

Answer:

<em>The force exerted by each string is 25 N</em>

Explanation:

<u>Net Force</u>

The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.

The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.

Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:

F + F - W

The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:

F + F - W = 0

2F = W

F = W/2 = 50 N/2

F = 25 N

The force exerted by each string is 25 N

7 0
3 years ago
A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1
vichka [17]

1) 26.6 m

Along the horizontal direction, the lunch pail is moving with a uniform motion (constant speed), since there are no forces acting in this direction.

Therefore, the distance travelled horizontally after a time t is given by:

d=v_x t

where we know

v_x = 1.50 m/s is the horizontal velocity

d = 3.50 m is the distance covered horizontally

Solving for t, we find the total time of the motion:

t=\frac{d}{v_x}=\frac{3.50}{1.50}=2.33 s

Now we know that the pail takes 2.33 s to fall to the ground. We can now consider the vertical motion of the pail, which is a free fall motion, so the vertical displacement is given by the equation

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

Substutting t = 2.33 s, we find how fat the pail has fallen:

s=\frac{1}{2}(9.8)(2.33)^2=26.6 m

2) 10.7 m

In this case, we know instead the vertical displacement:

s=2.50\cdot 10^2 m = 250 m

Therefore, we can use the same equation again

s=ut+\frac{1}{2}at^2

To find the total time of motion:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(250)}{9.8}}=7.14 s

We know that along the horizontal direction, the velocity is constant:

v_x = 1.50 m/s

So, the horizontal distance covered in this time is

d=v_x t = (1.50)(7.14)=10.7 m

6 0
4 years ago
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