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7nadin3 [17]
2 years ago
15

What is a question that an engineer might have about a can opener?

Physics
1 answer:
GuDViN [60]2 years ago
8 0

Answer:

Where can I get a can opener? hahaha

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Pilots can be tested for the stresses of flying high-speed jets in a whirling "human centrifuge," which takes 1.2min to turn thr
bearhunter [10]
Sure.
Can I use your answer to part-'a' ?

If the angular acceleration is actually 32 rev/min², than
after 1.2 min, it has reached the speed of

                 (32 rev/min²) x (1.2 min)  =  38.4 rev/min .

Check:

If the initial speed is zero and the final speed is 38.4 rpm,
then the average speed during the acceleration period is

                  
(1/2) (0 + 38.4)  =  19.2 rpm  average

At an average speed of  19.2 rpm for 1.2 min,
it covers

                   (19.2 rev/min) x (1.2 min)  =  23.04 revs .

That's pretty close to the "23" in the question, so I think that
everything here is in order.
4 0
3 years ago
Read 2 more answers
Please answer me my question​
Angelina_Jolie [31]
3 - b) weight decreases
4 -a) 50 kg as mass is same everywhere
5 - b) 200 dynes
5 0
3 years ago
____________ are used to calculate the distance a continent has moved in a year. a. Space satellites c. Laser beams b. Mirrors d
Law Incorporation [45]
<span> Space satellites, laser beams, mirrors</span> are used to calculate the distance a continent has moved in a year.

Therefore, your correct answer would be "all of the above".
4 0
3 years ago
The magnitude of the electric current is directly proportional to the _____ of the electric field.
Sedbober [7]
Is proportional to the CHANGE.

hope this helps
3 0
3 years ago
Read 2 more answers
a boy throws a ball straight up into the air. it reaches its highest point after 4 seconds.how fast was the ball going when it l
baherus [9]

Answer:

Explanation:

The most important thing to remember about parabolic motion in physics is that when an object reaches its max height, the velocity right there at the highest point is 0. Use this one-dimensional motion equation to solve this problem:

v = v₀ + at and filling in:

0 = v₀ + (-9.8)(4.0) **I put in 4.0 for time so we have more than just 1 sig fig here**

0 = v₀ - 39 and

-v₀ = -39 so

v₀ = 39 m/s

3 0
2 years ago
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