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7nadin3 [17]
2 years ago
15

What is a question that an engineer might have about a can opener?

Physics
1 answer:
GuDViN [60]2 years ago
8 0

Answer:

Where can I get a can opener? hahaha

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What do you make when you dissolve sugar in water?
AlladinOne [14]

It also takes energy to break the hydrogen bonds in water that must be disrupted to insert one of these sucrose molecules into solution. Sugar dissolves in water because energy is given off when the slightly polar sucrose molecules form intermolecular bonds with the polar water molecules.

I hope this helped :)

5 0
3 years ago
Can I apply my homework questions about physic?
docker41 [41]

Answer:

mhm

Explanation:

3 0
3 years ago
Read 2 more answers
a large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the blo
oksano4ka [1.4K]

The correct answer is Equal to the weight of the block.

We are aware that when an object floats, the water it displaces weighs the same as the weight of the floating body. The upthrust is now equivalent to the body weight in this situation. The beaker is overflowing with water in this instance. The body was then created to float into it. When it reaches equilibrium in water, it expels water that must have been the same weight as it. Over the edge, the liquid spilled, collecting on the tray.

Therefore, the amount of water gathered on the tray must match the weight of the person floating.

Learn more about weight here-

brainly.com/question/10069252

#SPJ4

5 0
2 years ago
a) A Kuiper Belt Object orbits the Sun with an average orbital distance of 40 AU. What is its orbital period? Round your answer
denpristay [2]

Answer:

253 years

Explanation:

a = Distance in Astronomical units from the sun = 40 AU

P = Orbital period in years

From Kepler's law we have

P^2=a^3

\Rightarrow P^2=40^3

\Rightarrow P^2=64000

\Rightarrow P=\sqrt{64000}

\Rightarrow P=252.982212813

\Rightarrow P\approx 253\ years

The orbital period of the Kuiper belt object is 253 years.

7 0
3 years ago
(d) If η = 40% and TH = 427°C, what is TC, in °C?
Brrunno [24]

Answer:

T_C=256.2^{\circ}C

Explanation:

Given that,

Efficiency of heat engine, \eta=40\%=0.4

Temperature of hot source, T_H=427^{\circ}C

We need to find the temperature of cold sink i.e. T_C. The efficiency of heat engine is given by :

\eta=1-\dfrac{T_C}{T_H}

T_C=(1-\eta)T_H

T_C=(1-0.4)\times 427

T_C=256.2^{\circ}C

So, the temperature of the cold sink is 256.2°C. Hence, this is the required solution.

3 0
3 years ago
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