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nordsb [41]
3 years ago
10

A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slo

wing down at 2.0 m/s2?
Physics
1 answer:
hjlf3 years ago
5 0

Answer:

360 N

Explanation:

m = 30kg    u = 2 m/s     a = -2m/s/s

Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

F = ma

F = 30 * -2

F = -60 N (the negative sign tells us that the force is acting downwards)

Now, calculating the force applied on the box due to gravity

letting g = -10m/s/s

F = ma

F = 30 * -10

F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

-300 + (-60) = -360 N

<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

Therefore tension on the force = <u>360 N</u>

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<h3></h3><h3>What is angular acceleration?</h3>

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to learn more about angular acceleration go to - brainly.com/question/21278452

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