Question

How many fluorine atoms are in 750.0 mL of a 0.500M HF solution?

Answer 1

Answer:

$2.26 \times 10^{23}atomsF$

Explanation:

Step 1: Given data

• Molarity of the HF solution (M): 0.500 M

• Volume of the solution (V): 750.0 mL

Step 2: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

750.0 mL × 1 L/1000 mL = 0.7500 L

Step 3: Calculate the moles of HF

We will use the following expression.

n = M × V

n = 0.500 mol/L × 0.7500 L = 0.375 mol

Step 4: Calculate the atoms of F in 0.375 moles of HF

We will use the following relationships:

• 1 mole of HF contains 1 mole of atoms of F.

• 1 mole of atoms of F contains 6.02 × 10²³ atoms of F (Avogadro's number).

$0.375 mol HF \times \frac{1 mol F}{1 molHF} \times \frac{6.02 \times 10^{23}atomsF }{1 mol F} = 2.26 \times 10^{23}atomsF$