What is the potential energy of a 1000 kg-ball that is on the ground?

Newtons third law of motion states that if a force is exerted on an object, another force occurs that, A. is equal in speed and

Deffense [45]

Answer:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

Explanation:

8 0

4 years ago

Consider a mass initially moving at 7.50 m/s. How does it take to move 3.5 km (Be sure to convert to meters) if it accelerates a

Tomtit [17]

The mass is moving by uniformly accelerated motion, with initial velocity $v_i=7.50 m/s$ and acceleration $a=0.55 m/s^2$ . Its position at time t is given by the following law:
$x(t)=v_i t + \frac{1}{2}at^2$
where we take the initial position $x_i=0$ since we are only interested in the distance traveled by the mass.

If we put $x(t)=d=3.5 km=3500 m$ into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
$\frac{1}{2}at^2+v_it-d=0$
$4.9t^2+7.5t-3500 =0$
And the two solutions for the equation are:
$t=-25.5 s$ --> negative, we can discard it
$t=24.0 s$ --> this is the solution to our problem

5 0

4 years ago

Carey and Marcy are performing a lab to determine the speed of sound in air with the apparatus that was demonstrated in the vide

andre [41]

Answer:

the frequency is the fundamental and distance is L = ¼ λ

Explanation:

This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is

λ = 4 L

In this case L = 19.4 cm = 0.194 m

let's use the relationship between wave speed and wavelength frequency and

v = λ f

where the frequency is f = 440 Hz

v = 4 L f

let's calculate

v = 4 0.194 440

v = 341.44 m / s

so the frequency is the fundamental and distance is

L = ¼ λ

5 0

4 years ago

You performed an experiment in which you measured the amount of water leaking through different types of roofs. For one roof, yo

Ostrovityanka [42]

Given:
m = 13.2 oz, the mass of water measured

Note that
$1 \, oz = (1 \, oz)*( \frac{1}{16} \, \frac{lb}{oz} )*( \frac{1}{2.2} \, \frac{kg}{lb} ) = 0.0284 \, kg$

Answer: 0.0284 kg

6 0

3 years ago

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One of two nonconducting spherical shells of radius a carries a charge Q uniformly distributed over its surface, the other carri

lisabon 2012 [21]

Answer:

Explanation:

A ) The spheres are non conducting , charge will not move on the surface so neutralization of charge by + ve and - ve charge is not possible. Charges will remain intact on them . The electric field inside them will be zero . Electric field outside shell will not be spherically symmetrical . Lines of force will emanate from the surface of positively charged shell outwardly oriented and end at negatively charged shell .

B )

distance between the centres of spherical shell

= 2 a

potential energy of charges

= k q₁ x q₂ / R

= k x - Q x Q / ( 2a )

= - k Q²/ 2a

So work needed to separate them to infinity will be equal to

= k Q²/ 2a

6 0

3 years ago