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Mademuasel [1]
3 years ago
7

20 points?!!!!!!please help I need this asap

Physics
1 answer:
IgorLugansk [536]3 years ago
6 0
F - F_f = ma

We are trying to find F.

F - 15 = 30(1.5)

F - 15 = 45

F = 60 N
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What is latent heat? Group of answer choices Energy released when water evaporates. Energy hidden in water vapor in the air. Ene
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Answer:

Energy absorbed or hidden when water evaporates

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The heat that is required to make a phase change is known as latent heat.

A phase change occurs when matter changes state. For example from solid to liquid, from liquid to gas, among others.

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So the answer is:

  • Energy absorbed or hidden when water evaporates.

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is the science that manages the database, digital tools, and software used by both medicine and forensic science to store and an
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8 0
3 years ago
You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be
Alex

Answer:

The amplitude  is  A =  90.2 \ m

Explanation:

From the question we are told that

    The frequency of when sound is approaching observer is   f = 392 Hz

     The frequency as the move away from observer  is  f_ a =  330 \ Hz

    The time between the pitch are t =  10 \ s

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

       T =  2 t

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

          T = \frac{2 \pi}{w}

Where  w is the angular velocity

=>   \frac{2 \pi}{w}  =  2 * 10

=>   w =  0.314 \ rad/sec

Now using Doppler Effect,

   The source of the sound is approaching the observer

The

          f = f_o (\frac{v}{v- wA} )

         392  = f_o (\frac{v}{v- wA} )

Where A is the amplitude

    So when the source is moving away from the observer

         f_a =  f_o (\frac{v}{v+ wA} )  

        330  =  f_o (\frac{v}{v+ wA} )  

Here  f_o is the fundamental frequency

Dividing the both equation  we have

           \frac{392}{330}  =  \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}

           1.1878  = \frac{v+wA}{v-wA}

         1.1878 v -  1.1878 wA = v+wA

        1.1878 v = 2.1878 wA

=>     A =  \frac{(0.1878 * (330))}{(2.1878)* (0.314)}

         A =  90.2 \ m

7 0
3 years ago
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