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Lelu [443]
3 years ago
14

A car came to a stop from a speed of 35 m/s in a time of 8.1 seconds. What was the acceleration of the car?

Physics
2 answers:
uranmaximum [27]3 years ago
5 0
Simply subtract the two velocities and divide by 8.1,

\frac{0 - 35}{8.1} = - 4.32

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
Ne4ueva [31]3 years ago
4 0

Answer:

The acceleration of the car is -4.32 m/s^2.

(C) is correct.

Explanation:

Given that,

Speed of car u= 35 m/s

Time t = 8.1 s

We need to calculate the acceleration

using equation of motion

v = u+at

Where, v = final velocity

u = initial velocity

t = time

a = acceleration

0=35+a\times8.1

a = -\dfrac{35}{8.1}

a = -4.32\ m/s^2

Hence, The acceleration of the car is -4.32 m/s^2.

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3 years ago
A 3.50 cm tall object is held 24.8 cm from a lens of focal length 16.0 cm. What is the image height?
Mandarinka [93]

Answer:

<h2>6.36 cm</h2>

Explanation:

Using the formula to first get the image distance

1/f = 1/u+1/v

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u = object distance

v = image distance

Given f = 16.0 cm, u = 24.8 cm

1/v = 1/16 - 1/24.8

1/v = 0.0625-0.04032

1/v = 0.02218

v = 1/0.02218

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To get the image height, we will us the magnification formula.

Mag = v/u = Hi/H

Hi = image height = ?

H = object height = 3.50 cm

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Hi = (45.09*3.50)/24.8

Hi = 6.36 cm

The image height is 6.36 cm

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What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?
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The car's velocity is (distance + direction) / (time) =

                                 (75 km-north) / (1.5 hrs)  =

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