Force of 500 N is acting on the parachutist.
Parachutist applies 500 N force in downward direction.
Answer:
300 N upward
Solution:
Parachutist feels air resistance of 800 N.
Thus, 800 N of force is acting in upward direction.
Total force acting on the parachutist is given by,
= air resistance force - force of parachutist
= 800-500
= 300 N
Direction of force is in upward direction because the air resistance force is more than force of parachutist.
In order to determine the acceleration of the block, use the following formula:

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

Then, you have:

by solving for a, you obtain:

In this case, you have:
k: spring constant = 100N/m
m: mass of the block = 200g = 0.2kg
x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m
Replace the previous values of the parameters into the expression for a:

Hence, the acceleration of the block is 10 m/s^2
The last one is correct (D)
The answer is he weighs 187.39 LBS/Pounds
It doesn't mean that the climate is changing, it is probably just the morning dew.