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Arisa [49]
3 years ago
8

Which changes in an electric motor will make the motor stronger? Check all that apply.

Physics
2 answers:
Doss [256]3 years ago
7 0

Answer:

using a stronger permanent magnet

increasing current in the electromagnet

decreasing the distance between the magnets

Explanation:

As we know the working of magnet is such that when current flows in the coil then due to strong magnetic field the coil will have tendency to rotate.

This is due to the torque on the coil which is given by

\tau = NiABsin\theta

now if we need to make the motor to be more strong then we need more torque on it which will be increased by

B = due to stronger magnet or by placing the magnets more closer to each other

i = by increasing the current in the coil

Blababa [14]3 years ago
4 0

Using a stronger magnet; Increasing the current in the magnet; Decreasing the distance between the magnets

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The distance covered by the proton is 48.4 m

Explanation:

The electric field produced by an electrically charged infinite plane is given by

E=\frac{\sigma}{2\epsilon_0}

where in this case,

\sigma = -1.10\cdot 10^{-6} C/m^2 is the surface charge density

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

Substituting,

E=\frac{-1.10\cdot 10^{-6}}{2(8.85\cdot 10^{-12})}=-5.65\cdot 10^4N/C

And the direction is towards the plane (because the charge is negative).

The electric force on the proton due to this field is

F=qE

where

q=1.6\cdot 10^{-19}C is the proton charge

Substituting,

F=(1.6\cdot 10^{-19})(-5.65\cdot 10^4)=-9.0\cdot 10^{-15} N

where the direction is toward the plane.

Now we can calculate the proton's acceleration using Newton's second law:

a=\frac{F}{m}

where

m=1.67\cdot 10^{-27}kg is the proton mass

Substituting,

a=\frac{-9.0\cdot 10^{-15}}{1.67\cdot 10^{-27}}=-5.4\cdot 10^{-12} m/s^2

Now we can finally apply the following suvat equation for accelerated motion to find the distance travelled by the proton:

v^2-u^2=2as

where

v = 0 is the final velocity

u=2.40\cdot 10^7 m/s is the initial velocity

a is the acceleration

s is the distance covered

And solving for s,

s=\frac{v^2-u^2}{2a}=\frac{0-(2.4\cdot 10^7)^2}{2(-5.4\cdot 10^{12})}=53.3 m

Therefore, the closest answer is 48.4 m.

Learn more about accelerated motion:

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Answer:

d

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The average thickness of a sheet of the paper is 0.1 mm.

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average thickness = 6 mm/60 sheets = 0.1 mm /sheet

Thus, the average thickness of a sheet of the paper is 0.1 mm.

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n = 32,000 cm³/400 cm³

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