1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zalisa [80]
3 years ago
5

La lumière des étoiles

Physics
1 answer:
madam [21]3 years ago
8 0
La lumière qui vient des étoiles.
You might be interested in
Find the ratio of the final speed of the electron to the final speed of the hydrogen ion, assuming non-relativistic speeds. Take
KiRa [710]

Answer:

\frac{V_{e}}{V_{h}}=0.428*10^{2}

Explanation:

From conservation of energy states that

K_{i}+v_{i}=v_{f}+K_{f}\\ as\\K_{i}=0\\K_{f}=1/2mv^{2}\\ v_{i}=qv\\v_{f}=0\\So\\qv=1/2mv^{2}\\ v=\sqrt{\frac{2qv}{m} }\\ Velocity_{electron}=\sqrt{\frac{2qv}{m_{e}} }\\Velocity_{hydrogen}=\sqrt{\frac{2qv}{m_{h}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{\frac{2qv}{m_{e}}}{\frac{2qv}{m_{h}}}}\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{m_{h}}{m_{e}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{1.67*10^{-27} }{9.11*10^{-31} } }\\\frac{V_{e}}{V_{h}}=0.428*10^{2}

5 0
3 years ago
Why does a geostationary satellite must orbit around Earth's equator, rather than in some other orbit (such as around the poles)
LiRa [457]

Answer:

A satellite on non-equatorial orbit would show daily motion even if its period is exactly 1 sidereal day.

Explanation:

5 0
2 years ago
What is static friction?​
givi [52]

Answer:

Plzzzzzzzzzzzzzzzz brainliest

Explanation:

In static friction, the frictional force resists force that is applied to an object, and the object remains at rest until the force of static friction is overcome. In kinetic friction, the frictional force resists the motion of an object. ... The frictional force itself is directed oppositely to the motion of the object.

7 0
2 years ago
The frequency of a wave is 250hz. What is the period
antoniya [11.8K]

Answer:

Hope it helps for you :)))))

8 0
3 years ago
A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Anoth
Karo-lina-s [1.5K]

Answer:

8.467 gm

Explanation:

The law governing this problem is "The Law of Constant Composition "

As per this law, all compounds irrespective of their origin and source have the same composition and properties  in their purest form

It is a simple proportion and ratio related problem.

1.50 grams of carbon require 2.0 grams of oxygen

1.0 grams of carbon will require oxygen

=\frac{2}{1.5}

6.35 grams of carbon will require oxygen

\frac{2}{1.5}\times6.35= 8.4666\\= 8.467

6 0
3 years ago
Other questions:
  • Communications satellites are placed in a circular orbit where they stay directly over a fixed point on the equator as the earth
    15·1 answer
  • A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The
    6·1 answer
  • Find the energy (in eV) of a ground state electron in a He II (He + ) atom. (b.) Find the amount of energy (in eV) needed to ion
    10·1 answer
  • In old times, before there were train signals, people who worked on the railroad would often put their ear down to the train tra
    7·1 answer
  • A person riding in a hot air air balloon basket ascends to 1000 ft above the ground. What happened to the atmospheric pressure a
    5·1 answer
  • The quantum theory of radiation reflects:
    8·1 answer
  • An alumium rod when measured with a steel scale both being at 25 degree celcius appears to be 1 meter long. If the scale is corr
    12·2 answers
  • 500 J of work is used to decrease the angular velocity of a disk from 65 rad/s to 52 rad/s.What is the rotational inertia of the
    15·1 answer
  • A truck is traveling at a speed of 50 km/h. What happens when the truck slows down?
    11·1 answer
  • A current of 0.050 amps flows in a circuit element with a resistance of 25 ohms what is the voltage drop across the circuit elem
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!