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zalisa [80]
3 years ago
5

La lumière des étoiles

Physics
1 answer:
madam [21]3 years ago
8 0
La lumière qui vient des étoiles.
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A 3000-N force gives an object an acceleration of 15m/s^2 the mass of the object is?
Shkiper50 [21]

Answer:c will be answer

Explanation:Because u know F=ma so if we wanna know m then we should move a on left side and it will be in divide with f after moving on left side so

M=F/A

7 0
3 years ago
Read 2 more answers
and an ideal spring of unknown force constant. The oscillator is found to have a period of 0.157 s and a maximum speed of 2 m/s
DENIUS [597]

Answer:

k = 1073.09 N/m

A = 0.05 m

Explanation:

Given:

- Time period T = 0.147 s

- maximum speed V_max = 2 m/s

- mass of the block m = 0.67 kg

Find:

- The spring constant k

- The amplitude of the motion A.

Solution:

- A general simple harmonic motion is modeled by:

                                     x (t) = A*sin(w*t)

- The velocity of the above modeled SHM is:

                                     v = dx / dt

                                     v(t) = A*w*cos(w*t)

- Where A is the amplitude in meters, w is the angular speed rad/s and time t is in seconds.

- We can see that maximum velocity occurs when (cos(w*t)) maximizes i.e it is equal to 1 or -1. Hence,

-                                      V_max = A*w

- Where w is related to mass of the object and spring constant k as follows,

                                       w = sqrt ( k / m )

- The relationship between w angular speed and Time period T is:

                                       w = 2*pi / T

- Equating the above two equations we have,

                                        m*(2*pi / T)^2 = k

- Hence,                           k = 0.67*(2*pi / 0.157)^2

                                        k = 1073.09 N / m

- So, amplitude A is:

                                        A = V_max*sqrt ( m / k )

                                        A = 2*sqrt ( 0.67 / 1073.09 )

                                        A = 0.05 m      

6 0
4 years ago
If an object has the the mass of 3kg, calculate the force acting on it.
Verdich [7]
Well first, how do we determine force?

6 0
3 years ago
Free charges do not remain stationary when close together. To illustrate this, calculate the magnitude of the instantaneous acce
ASHA 777 [7]

Answer:

a=2.304×10¹⁶m/s²

Explanation:

Given data

Distance d=2.5 nm=2,5×10⁻⁹m

Mass of proton m=1.6×10⁻²⁷kg

charge of proton q=1.6×10⁻¹⁹C

To find

acceleration a

Solution

Apply the Coulombs Law

F=k\frac{q_{1}q_{2}  }{r^{2} }

Where k is coulombs constant (k=9×10⁹Nm²/C²)

q=q₁=q₂

r=d

So

F=k\frac{|q^{2} |}{d^{2} }\\ as \\F=ma\\ma=k\frac{|q^{2} |}{d^{2} }\\a=\frac{k}{m} \frac{|q^{2} |}{d^{2} }\\a=\frac{(9*10^{9} )*(1.6*10^{-19} )^{2} }{(1.6*10^{-27} )*(2.5*10^{-9} )^{2} }\\ a=2.304*10^{16}m/s^{2}  

4 0
4 years ago
Is there supposed to be a slit at the top of your adams apple?
Allushta [10]
No, there isn't. Please consult your doctor if this is the case with yours or someone you know.
7 0
3 years ago
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