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photoshop1234 [79]
2 years ago
5

Your science teacher has provided the following materials to investigate the factors that affect the strength of electric and ma

gnetic forces.
• large iron nail – 5 mm diameter

• 100 cm of thinly wrapped copper wire

• D battery

• electrical tape

• wire strip

• thumb tacks -assorted sizes

• paperclips – assorted sizes

Design an investigation you could carry out to determine the factors that affect the strength of electrical and magnetic forces.
Physics
1 answer:
kodGreya [7K]2 years ago
3 0

The strength of the electric field can be estimated as force per electric charge, whereas the strength of a magnetic field depends on the force of electrons and velocity.

<h3>Whta is a magnetic field?</h3>

A magnetic field can be defined as magnetic work exerted on electric charges that are in motion (movement).

Conversely, an electric field is an area where an electric current is applied and electron force can be estimated per Volts per Meter.

In conclusion, the strength of the electric field can be estimated as force per electric charge, whereas the strength of a magnetic field depends on the force of electrons and velocity.

Learn more about magnetic fields here:

brainly.com/question/14411049

#SPJ1

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What condition is required for cloud formation in the atmosphere?
Vedmedyk [2.9K]

Answer: To form a cloud, the air that rises must cool to the point where some of the water vapor molecules "clump together" at a faster pace than they are pulled apart by their thermal energy. These molecules then condense to form the clouds and water droplets.

7 0
4 years ago
The nucleus of some isotopes will spontaneously undergo nuclear decay. These isotopes are said to be radioactive. What causes th
Dmitry_Shevchenko [17]

Answer:

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The electric force and nuclear forces are in opposition to each other

Nuclear forces disintegrate protons

There are too many electrons in its orbitals

The electric force causes electrons to be released

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7 0
2 years ago
A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s
Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

Explanation:

Given

Weight of sledge hammer = 2.30 kilogram

Speed of sledge hammer = 62.7 meter per second

Kinetic energy is equal to half the product of mass and velocity square

K E = \frac{1}{2} mv^2

Substituting the value of mass and velocity, we get -

KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

\frac{1}{4} * 4520.9835\\= 1130.246

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

8 0
3 years ago
Read 2 more answers
During what intervals was jenny negatively accelerating
PolarNik [594]

Jenny's acceleration was negative during the intervals of time when her speed was decreasing.

That's really all we can tell, because you really haven't given us any information except her name.

5 0
4 years ago
A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

F=BIL sin theta

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

\frac{y}{x} =2

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j

L = 0.098 i+0.197 j-0.22k

Then,

F = I (L × B)

F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))

F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )

F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)

F = -1.415 j-1.271 k

The magnitude of force on the wire will be

F = \sqrt{(-1.415)^{2}+(-1.27)^{2}  } = \sqrt{3.615}=1.90 N

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0
4 years ago
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