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coldgirl [10]
3 years ago
13

Two large parallel conducting plates are 8.0 cm apart and carry equal but opposite charges on their facing surfaces. The magnitu

de of the surface charge density on either of the facing surfaces is 2.0 nc/m2. Determine the magnitude of the electric potential difference between the plates.
Physics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

18.1 V

Explanation:

The electric field between two parallel plates is given by the equation:

E=\frac{\sigma}{\epsilon_0}

where

\sigma is the charge surface density

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

For the plates in this problem,

\sigma = 2.0 nC/m^2 = 2.0\cdot 10^{-9} C/m^2

So, the magnitude of the electric field is

E=\frac{2.0\cdot 10^{-9}}{8.85\cdot 10^{-12}}=226.0 V/m

Now we can find the potential difference between the plates, which is given by

\Delta V = E d

where

d = 8.0 cm = 0.08 m is the separation between the plates

Substituting,

\Delta V=(226.0)(0.08)=18.1 V

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velikii [3]

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5 0
1 year ago
Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is  Av with A the cross section area and v the velocity,

so,

A_1V_1=A_2V_2

A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}

the diameter decreases 86% so

d_2 = 0.86d_1

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}

Thus, speed in smaller section is 48.6 m/s

3 0
3 years ago
A gas occupies a volume of 1.0 m3 in a cylinder at a pressure of 120kPa. A piston compresses the gas until the volume is 0.25m3,
Hoochie [10]

Answer:

Approximately 480\; \rm kPa, assuming that this gas is an ideal gas.

Explanation:

  • Let V(\text{Initial}) and P(\text{Initial}) denote the volume and pressure of this gas before the compression.
  • Let V(\text{Final}) and P(\text{Final}) denote the volume and pressure of this gas after the compression.

By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:

\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}.

Note that in Boyle's Law, P is inversely proportional to V. Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.

For this particular question:

  • V(\text{initial}) = 1.0\; \rm m^3.
  • P(\text{Initial}) = 120\; \rm kPa.
  • V(\text{final}) = 0.25\; \rm m^3.
  • The pressure after compression, P(\text{Final}), needs to be found.

Rearrange the equation to obtain:

\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial}).

Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.

\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}.

4 0
3 years ago
A ​46-ton monolith is transported on a causeway that is 3500 feet long and has a slope of about 3.7. How much force parallel to
ludmilkaskok [199]

Answer:

2.9tons

Explanation:

Note that On an incline of angle a from horizontal, the parallel and perpendicular components of a downward force F are:

parallel ("tangential"): F_t = F sin a

perpendicular ("normal"): F_n = F cos a

At a=3.7 degrees, sin a is about 0.064 and with F = 46tons:

F sin a ~~ (46 tons)*0.064 ~~ 2.9tons

Also see attached file

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3 years ago
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