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4 years ago

A ball of mass 2.0 kg falls vertically and hits the ground with speed 7.0 ms-1 as shown below.

Physics

2 answers:

Doss [256]4 years ago

8 0

Answer:

Magnitude of the change in momentum of the ball is 8.0Ns

Explanation:

Momentum of a body is defined as the product of mass of the body and its change in velocity.

Momentum = mass × change in velocity

If change in velocity = final velocity - initial velocity

Momentum = velocity (final velocity-initial velocity)

Momentum = m(v-u)

Given;

Mass of the ball m = 2.0kg

If the ball leaves the ground with a vertical speed 3.0 m/s,

Initial velocity of the ball u = 3.0m/s

If the ball falls vertically and hits the ground with speed 7.0 m/s,

Final velocity of the ball v = 7.0m/s

Substituting the given datas into the momentum formula will be equivalent to;

Momentum = m(v-u)

Momentum = 2.0(7-3)

Momentum = 2×4

Momentum = 8.0kgm/s or 8.0Ns

Magnitude of the change in momentum of the ball is 8.0Ns

Sauron [17]4 years ago

7 0

Answer:

8.0 Ns

Explanation:

Change in momentum is given as:

Final momentum - Initial momentum

= m*v - m*u

Where m = mass of ball

v = final velocity

u = initial velocity

Change in momentum = (2.0 * 3.0) - (2.0 * 7.0)

= 6.0 - 14.0 = -8.0 Ns

The magnitude will be |-8.0| = 8.0 Ns

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A stone is thrown from the top of a building with an initial velocity of 20 m/s downward. The top of the building is 60 m above

erastova [34]

Answer:

t = 2 s

Explanation:

In order to find the time taken by the stone to fall from the top of the building to the ground we can use 2nd equation of motion. 2nd equation of motion is as follows:

s = Vit + (0.5)gt²

where,

t = time = ?

Vi = Initial Velocity = 20 m/s

s = height of building = 60 m

g = 9.8 m/s²

Therefore,

60 m = (20 m/s)t + (0.5)(9.8 m/s²)t²

4.9t² + 20t - 60 = 0

solving this quadratic equation we get:

t = -6.1 s (OR) t = 2 s

Since, the time cannot be negative in magnitude.

Therefore,

6 0

3 years ago

Which of the following statements are true about the lenses used in eyeglasses to correct nearsightedness and farsightedness? (T

Slav-nsk [51]

Answer:

A: They produce a real image.

Explanation:

The images formed on the retina of the eye for a normal visibility must always be real.

Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.

The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.

4 0

3 years ago

A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on

telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

$sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m$

The work done by gravity on the boy is calculated as;

W = P.E = mgh

= 32kg x 9.8m/s² x 1.928m

= 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0

3 years ago

Calculate the pressure of an enclosed fluid on which a force of 150 N is exerted over an area of 10 cm2. give the answer in pasc

jek_recluse [69]

The pressure of the enclosed fluid is 150000Pa

3 0

4 years ago

A marble dropped in still water will create circular ripples or waves. the radius of each circular wave will increase 4 centimet

Gnom [1K]

The circumference of the circle after t seconds = 25.12 t

Given data,

The radius of each circular wave will increase by four centimeters per second (cm/s)

In 1 second of circular wave radius = 4cm

In 1*t second of circular wave radius = 4t cm

As a result, the radius of the circular wave after t seconds is 4t cm.

We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.

As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t

= 8πt

( Taking π = 3.14 )

As a result, the circumference of the circle after t seconds = 8πt

= 3.14t

= 25.12t

Find more on circumference at : brainly.in/question/49774764

#SPJ4

5 0

2 years ago