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Nadusha1986 [10]
1 year ago
5

If the reactants of a reaction are HCI and NaOH, what could be a product?

Chemistry
1 answer:
Nutka1998 [239]1 year ago
6 0

Answer

HCl+NaOH=NaCl+H2O (NaCl+H20)=the product

is a double substitution reaction

so the product ,one of them will be or Nacl or Water(H2O)

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The mass of an iron(II) sulfate crystal is 8.36 g.How many moles of FeSO4 are in the crystal?
Yuki888 [10]

The number of moles present in the FeSO4 are 0.055 mol.

<u>Explanation:</u>

  • The mass of a substance containing the same number  atoms in 12.0 g of 12C is known as mole. One mole of any substance is equal to  6.023 x 10^23. The moles of a substance can be determined by using the formula,

                 Number of moles = mass in grams / molecular mass

Given,

    mass = 8.36 g,

    molecular mass of FeSO4 = 151.908 g / mol

         number of moles = 8.36 / 151.908

                                       = 0.055 mol.

5 0
3 years ago
Is the chemical reaction between magnesium metal and hydrochloric acid solution an acid base reaction?
Anika [276]

Answer:

No

Explanation:

The chemical reaction between magnesium metal and hydrochloric acid solution is not an acid - base reaction.

An acid - base reaction involves an acid and base to produce salt and water.

  • This reaction is called a neutralization reaction.
  • An acid is a substance that produces excess hydroxonium ions in solutions.
  • A base produces excess hydroxyl ions in solution.
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3 0
2 years ago
A solution of pH 5 is diluted 100 times. Find the pH of the resulting solution.
liq [111]
First, we calculate of the concentration of the H+ ions in the solution from the pH given. Then, calculate the new concentration after dilution. Calculation are as follows:

pH = -log[H+]
5 = -log[H+]
[H+] = 1 x 10^-5 M

M1V1 = M2V2
<span>1 x 10^-5 M (V1) = M2(100V1)
</span>M2 = 1 x 10^-7

pH =  -log[<span>1 x 10^-7</span>]
pH = 7

3 0
2 years ago
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4 0
3 years ago
Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
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8 0
3 years ago
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