Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2
The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s
Using S=ut+
2
1
at
2
∴ S=30×3+
2
1
×(−10)×3
2
=45m
Answer:
East component is: 18.64 m/s
Explanation:
If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:
East component = 32.5 m/s * sin(35) = 18.64 m/s
Answer: 4.03 m/s
Explanation: Kinetic energy is
KE = 1/2 m v²
So we derive the equation to have v.
v = √ 2KE / m
= 2 x 568 J / 70 kg
= 16.23
= √ 16.23
= 4.03 m/s
Answer:
90
Explanation:
take note that V= (velocity is distance over (divided by) time. so in this case its 198(distance) divided by 2.2 (time) =90