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miss Akunina [59]
3 years ago
8

Janice has just measured the density of an object. Which value is possible? (Density: D = )

Physics
2 answers:
babunello [35]3 years ago
6 0
It is 6 g/cm3 because density cannot be negative, and it is not speed in which the unit would be m/s.
Naily [24]3 years ago
4 0

Answer:

density = 6 g/cm^3

Explanation:

as we know that density is the ratio of mass and volume of the object

density = \frac{mass}{volume}

here we know that mass as well as volume both are always positive so the ratio of both can not be negative.

so we know that mass is measured in gram and volume is measured in cubic cm

so the density is measured in

density = \frac{gram}{cm^3}

so the correct answer must be positive and in terms of above units

so we have

density = 6 g/cm^3

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What is the magnitude of the total acceleration of point A after 2 seconds? The bar starts from rest and has a constant angular
monitta

Answer:

a_total = 2 √ (α² + w⁴) ,   a_total = 2,236 m

Explanation:

The total acceleration of a body, if we use the Pythagorean theorem is

          a_total² = a_T²2 + a_{c}²

where

the centripetal acceleration is

  a_{c} = v² / r = w r²

tangential acceleration

   a_T = dv / dt

angular and linear acceleration are related

         a_T = α  r

we substitute in the first equation

       a_total = √ [(α r)² + (w r² )²]

       a_total = 2 √ (α² + w⁴)

Let's find the angular velocity for t = 2 s if we start from rest wo = 0

        w = w₀ + α t

        w = 0 + 1.0 2

        w = 2.0rad / s

       

we substitute

        a_total = r √(1² + 2²) = r √5

        a_total = r 2,236

In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m

         a_total = 2,236 m

7 0
3 years ago
A 1.30-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v
atroni [7]

Answer:

1. t = 0.0819s

2. W = 0.25N

3. n = 36

4. y(x , t)= Acos[172x + 2730t]

Explanation:

1) The given equation is

y(x, t) = Acos(kx -wt)

The relationship between velocity and propagation constant is

v = \frac{\omega}{k}=\frac{2730rad/sec}{172rad/m}\\\\

v = 15.87m/s

Time taken, t = \frac{\lambda}{v}

= \frac{1.3}{15.87}\\\\=0.0819 sec

t = 0.0819s

2)

The velocity of transverse wave is given by

v = \sqrt{\frac{T}{\mu}}

v = \sqrt{\frac{W}{\frac{m}{\lambda}}}

mass of string is calculated thus

mg = 0.0125N

m = \frac{0.0125N}{9.8N/s}

m = 0.00128kg

\omega = \frac{v^2m}{\lambda}

\omega = \frac{(15.87^2)(0.00128)}{1.30}

\omega = 0.25N

3)

The propagation constant k is

k=\frac{2\pi}{\lambda}

hence

\lambda = \frac{2\pi}{k}\\\\\lambda = \frac{2 \times 3.142}{172}

\lambda = 0.036 m

No of wavelengths, n is

n = \frac{L}{\lambda}\\\\n = \frac{1.30m}{0.036m}\\

n = 36

4)

The equation of wave travelling down the string is

y(x, t)=Acos[kx -wt]\\\\becomes\\\\y(x , t)= Acos[(172 rad.m)x + (2730 rad.s)t]

without, unit\\\\y(x , t)= Acos[172x + 2730t]

7 0
3 years ago
A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove
NARA [144]

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

6 0
3 years ago
Read 2 more answers
Every winter I fly to Michigan. It's a total distance of 3900km. It takes 5 hours. What is my average speed?
olga_2 [115]
\frac{3900}{5} = 780\sf ~kilometer~per~hour

Your average speed is 780 kilometer per hour.
4 0
3 years ago
Read 2 more answers
As a 2.0-kg block travels around a 0.50-m radius circle it has an angular speed of 12 rad/s. The circle is parallel to the xy pl
Lynna [10]
It's 60.... i have used the formula
L=r^2mw
and didn't use the value 0.75...
6 0
3 years ago
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