Question

A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What was the maximum height of the ball

Answer 1

Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2


The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1
​
at
2

∴ S=30×3+
2
1
​
×(−10)×3
2
=45m

Answer 2

Answer:

h = 3.3 m

Explanation:

The ball falls from vertical rest

v² = u² + 2as

h = (8² - 0²) / (2(9.8)) = 3.26530...

h = 3.3 m when rounded to the two significant digits of the question numerals.