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REY [17]
3 years ago
8

A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What wa

s the maximum height of the ball
Physics
2 answers:
hram777 [196]3 years ago
8 0
Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2


The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1
​
at
2

∴ S=30×3+
2
1
​
×(−10)×3
2
=45m
lara [203]3 years ago
5 0

Answer:

h = 3.3 m

Explanation:

The ball falls from vertical rest

v² = u² + 2as

h = (8² - 0²) / (2(9.8)) = 3.26530...

h = 3.3 m when rounded to the two significant digits of the question numerals.

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