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REY [17]
3 years ago
8

A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What wa

s the maximum height of the ball
Physics
2 answers:
hram777 [196]3 years ago
8 0
Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2


The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1
​
at
2

∴ S=30×3+
2
1
​
×(−10)×3
2
=45m
lara [203]3 years ago
5 0

Answer:

h = 3.3 m

Explanation:

The ball falls from vertical rest

v² = u² + 2as

h = (8² - 0²) / (2(9.8)) = 3.26530...

h = 3.3 m when rounded to the two significant digits of the question numerals.

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Two children stand on a platform at the top of a curving slide next to a backyard swimming pool. At the same moment the smaller
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Answer:

Explanation:

i )

In a conservative field like gravitational field , loss of potential energy  or work done , depends upon the initial and final point and not the manner in which 2 nd point has been reached . Since the initial and final point is same in both the cases of straight and curved path , final velocity will remain same for both of them .

Hence , due to increased mass of larger child , his kinetic energy will be greater .

ii ) Since the initial and final point is same in both the cases of straight and curved path , final velocity will remain same for both of them .

iii ) Smaller child undergo free fall , therefore , he will fall with acceleration g . The larger child falls on curved path . So , he will have only a component of

vertical g at any moment  . hence average acceleration  will be less.

6 0
4 years ago
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Usimov [2.4K]

Answer:

Im pretty sure its b

4 0
3 years ago
If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th
Viktor [21]

Let us list out what we know from the question.

Initial Velocity V_{i}  = 0 since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity a = 9.8 m/s^{2}

Final Velocity V_{f} = ?

Using the equation, V^{2} _{f} = V^{2} _{i}  + 2aD and plugging in the known values, we get

V^{2} _{f}  = 0^{2}  + 2(9.8)(215)

Simplifying by taking square-root on both sides gives us V_{f} =  64.915 m/s

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0
3 years ago
As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o
MrRa [10]

Answer:

18.6012339739 A

Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

L = Length of wire = 55 cm

N = Number of turns = 4000

I = Current

Magnetic field is given by

B=\dfrac{\mu_0NI}{L}\\\Rightarrow I=\dfrac{BL}{\mu_0N}\\\Rightarrow I=\dfrac{0.17\times 0.55}{4\pi \times 10^{-7}\times 4000}\\\Rightarrow I=18.6012339739\ A

The current necessary to produce this field is 18.6012339739 A

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