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Sergeeva-Olga [200]
1 year ago
14

If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of

Chemistry
1 answer:
navik [9.2K]1 year ago
6 0

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

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10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

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≅ 10 days (1 sig. fig. based on given 1 gram mass)

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Determine the theoretical maximum moles of ethyl acetate, , that could be produced in this experiment. The reactant, acetic acid
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Answer:

0.1832 moles of ethyl acetate (C_{4}H_{8}O_{2})

Explanation:

1. Find the balanced chemical equation:

In the production of ethyl acetate, the acetic acid CH_{3}COOH reacts with ethanol to produce ethyl acetate C_{4}H_{8}O_{2} and water, that is:

CH_{3}COOH+C_{2}H_{5}OH=C_{4}H_{8}O_{2}+H_{2}O

2. Find the theoretical maximum moles of ethyl acetate C_{4}H_{8}O_{2}:

As the problem says that the acetic acid CH_{3}COOH is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:

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