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Aleksandr-060686 [28]
3 years ago
14

What is the energy of a wave with wavelength of 4.2 x 10-7 m. (Hint: Calculate for frequency first.)

Chemistry
1 answer:
erik [133]3 years ago
5 0

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

Energy (E) =.?

Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

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Green plants use light from the sun to drive photosynthesis. photosynthesis is a chemical reaction in which water (H2O) and carb
alexandr1967 [171]

Answer:

Mass of H₂O is 3.0g

Explanation:

The reaction equation is given as:

        6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Parameters that are known:

Mass of CO₂ used = 7.3g

Unknown: mass of water consumed = ?

Solution

To solve this kind of problem, we simply apply some mole concept relationships.

  • First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:

        Number of moles of CO₂ =  \frac{mass}{molar mass}

  • From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:

       6 moles of CO₂ reacted with 6 moles of H₂O(1:1)

  • We can then use the mole relationship with mass to find the unknown.

Workings

>>>>     Number of moles of CO₂ =?

          Molar mass of CO₂ :

              Atomic mass of C = 12g

               Atomic mass of O = 16g

        Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹

     Number of moles of CO₂ = \frac{7.3}{44} = 0.166moles

>>>>>>   if 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O

>>>>>> Mass of water consumed = number of mole of H₂O x molar mass

             Mass of H₂0 = 0.166 x ?

Molar mass of H₂O:

                 Atomic mass of H = 1g

                 Atomic mass of O = 16

 Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹

Mass of H₂O = 0.166 x 18 = 3.0g

7 0
3 years ago
What type of bond will form<br><br> Nitrogen and Tellurium
sineoko [7]

Answer: Vander waals

Explanation:

Tellurium is a chemical element with atomic number 52. It's symbol is Te.

Nitrogen is a chemical element with atomic number 14. Its symbol is N

VANDER WAALS bond is found between Nitrogen and Tellurium, just as in Tellurium(II) Nitrogen.

This bond is relatively weak compared to some other kinds of bonds.

That is why tellurium and most of its compounds are usually brittle and easily grounded.

So, Vander Waals bonds is the answer

4 0
3 years ago
Rationalize the following statements and give chemical reactions .
Dahasolnce [82]

Answer:

i do not no

Explanation:

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8 0
3 years ago
The second-order diffraction for a gold crystal is at an angle of 22.20o for X-rays of 154 pm. What is the spacing between the c
Alenkinab [10]

<u>Answer:</u> The spacing between the crystal planes is 4.07\times 10^{-10}m

<u>Explanation:</u>

To calculate the spacing between the crystal planes, we use the equation given by Bragg, which is:

n\lambda =2d\sin \theta

where,

n = order of diffraction = 2

\lambda = wavelength of the light = 154pm=1.54\times 10^{-10}m     (Conversion factor:  1m=10^{12}pm )

d = spacing between the crystal planes = ?

\theta = angle of diffraction = 22.20°

Putting values in above equation, we get:

2\times 1.54\times 10^{-10}=2d\sin (22.20)\\\\d=\frac{2\times 1.54\times 10^{-10}}{2\times \sin (22.20)}\\\\d=4.07\times 10^{-10}m

Hence, the spacing between the crystal planes is 4.07\times 10^{-10}m

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