Explanation:
It is given that,
Charge on electron, 
Mass of the electron, 
Speed of the electron, 
Magnetic field, B = 1 T (directed out of the page)
Let F is the magnetic force acting on the electron. It is given by :
Here, 
Using the right hand rule, the direction of magnetic force is upward to the plane of the paper. Also, the electron will follow the circular path. It is given by :
Hence, this is the required solution.
When undergoing an ultrasound, the transducer probe of the ultrasound machine transmits sound waves. It also receives the sound waves that are reflected back after it reaches a boundary.
The reflected waves are received by the probe and relayed to the ultrasound machine. The machine calculates the distance from the probe to the tissue or organ (boundaries) using the speed of sound in tissue and the time of the each echo's return. It then <span>displays the distances and intensities of the echoes on the display screen, forming a two dimensional image. </span>
Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately
Answer:
Total work done =force X displacement = 15 N X 2.5 m [ given F=15 N & d=2.5 m] W = 37.5 joules
Explanation:
this is just what i was able to find
