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andrey2020 [161]
3 years ago
6

You may need a piece of paper to write this down and understand. they have a box on a table with 3 arrows. one of them is pointi

ng both up and down and have a 4N above it and -4N on the bottom . they have a arrow on the left pointing to the left that has -2N to the side of it and the last arrow is on the rights pointing to the right that has 5N. and it says/ asks this
Analyzing the Net Force

Your job is to analyze the forces acting on this box to determine the net force acting on it. Look at the following diagram and read the information. Then answer the question.
A downward force of 4 N acts on the box. This is the box’s weight. Assume the table is strong enough to support the box, so the normal force acting on the box has a magnitude of 4 N. A left-pulling force of 2 N and a right-pulling force of 5 N act on the box too.

So, after considering the effects of all these forces, what is the net force acting on the box?

Remember that a force has both a magnitude (a number) and a direction. Therefore, be sure to include both of these in your answer and explain how you found your answer.
Physics
2 answers:
Jet001 [13]3 years ago
7 0
Is there 4 arrows? Cause from the question, it looks like there is four arrows, anyways, net force is defined as the sum of the forces. We can look at this from a component view point.

First lets take a look at vertical forces. There is a force pointing downwards by -4N, there is another force pointing upwards which is +4N. The sum of these forces is 0, so the net force is 0. This tells us that there is no force acting on the box in the vertical direction.

Next let's examine the horizontal forces. There is a force pointing back -2N and another force pointing in the positive direction 5N. The sum of these forces is 3N, meaning there is a force of 3N being applied in the positive x-direction, or to the right.

So the total net force is 3N to the right.
iris [78.8K]3 years ago
6 0

12N to the right on E2020.

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8 0
3 years ago
If you were to travel from the equator to the higher latitudes (near either pole) on Saturn, the differential rotation would cau
Dmitrij [34]

Answer:

Saturn's differential rotation will cause the length of a day measures to be longer by 0.4 hours

Explanation:

Differential rotation occurs due to the difference in angular velocities of an object as we move along the latitude of the or as we move into different depth of the object, indicating the observed object is in a fluid form

Saturn made almost completely of gas and has differential motion given as follows

Rotation at the equator = 10 hours 14 minutes

Rotation at high altitude = 10 hours 38 minutes

Therefore;

The differential rotation = 10 hours 38 minutes - 10 hours 14 minutes

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The differential rotation = 0.4 hours

Therefore, the measured day at the higher altitude will be 0.4 longer than at the equator.

8 0
3 years ago
A mechanic pushes a 3540 kg car from rest to a speed of v, doing 4864 J of work in the process. Find the speed v. Neglect fricti
topjm [15]

Answer:

1.66 m/s

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6 0
2 years ago
Suppose I have a vector that is 7 units long and that makes an angle of +30 degrees from the positive x-axis. I want to add to t
Vinil7 [7]

Answer:

sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j

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We have given first vector which has length of 7 units and makes an angle of 30° with positive x-axis

So x component of the vector =7cos30^{\circ}=7\times 0.866=6.06

y component of the vector =7sin30^{\circ}=7\times 0.5=3.5

So vector will be 6.06i+3.5j

Now other vector of length of 7 units and makes an angle of 120° with positive x-axis

So x component of vector  =7cos120^{\circ}=7\times -0.5=-3.5i

y component of the vector =7sin120^{\circ}=7\times 0.866=6.06j

Now sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j

5 0
3 years ago
A lamp draws a current of 0.1 A when it is connected to a 122-V source. (
Setler79 [48]
The power of the lamp would be calculated with the equation of ohm laws. P = U x I = 122V x 0.1A = 12.2W
4 0
3 years ago
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