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shepuryov [24]
4 years ago
5

in a human cannonball a person is shot from a cannon with a barrel that is 3.05 m long. 16700 J of work are done to accelerate t

he acrobat out of the cannon. what is the force exerted on the acrobat
Physics
1 answer:
ankoles [38]4 years ago
6 0
The work done to accelerate the acrobat is given by
W=Fd
where F is the force applied and d the distance of application of the force.
If the barrel is 3.05 m long, then d=3.05 m. Therefore we can find the force:
F= \frac{W}{d} = \frac{17600 J}{3.05 m} =5475 N
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\lambda=\frac{2}{1} \cdot 3.5 m=7.0 m


The wavelength of the 2nd harmonic is:

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The wavelength of the 4th harmonic is:

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