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shepuryov [24]
3 years ago
5

in a human cannonball a person is shot from a cannon with a barrel that is 3.05 m long. 16700 J of work are done to accelerate t

he acrobat out of the cannon. what is the force exerted on the acrobat
Physics
1 answer:
ankoles [38]3 years ago
6 0
The work done to accelerate the acrobat is given by
W=Fd
where F is the force applied and d the distance of application of the force.
If the barrel is 3.05 m long, then d=3.05 m. Therefore we can find the force:
F= \frac{W}{d} = \frac{17600 J}{3.05 m} =5475 N
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A ________ is a government-regulated maximum price for goods.
Simora [160]
<span>D. price ceiling
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8 0
2 years ago
Compute the density in g/cm^3 of a piece of metal that had mass of 0.485 kg and a volume of 52cm^3
steposvetlana [31]

Answer:

9.3 g/cm³

Explanation:

First, convert kg to g:

0.485 kg × (1000 g / kg) = 485 g

Density is mass divided by volume:

D = (485 g) / (52 cm³)

D = 9.33 g/cm³

Rounding to two significant figures, the density is 9.3 g/cm³.

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3 years ago
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pav-90 [236]
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2 years ago
. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to
d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

B = 5 \times 10^{-6} T

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

B = \frac{\mu_o i}{2\pi r}

here we we will find the magnetic field due to wire which is along x axis is given as

i = 30 A

r = 2 m

now we have

B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}

B_1 = 3\times 10^{-6} T into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

i = 40 A

r = 2 m

now we have

B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}

B_2 = 4\times 10^{-6} T along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

B = \sqrt{B_1^2 + B_2^2}

B = 5 \times 10^{-6} T

5 0
3 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
2 years ago
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