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almond37 [142]
3 years ago
6

What is the general shape of the graph line?

Physics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

A

Explanation:

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Find the mass. 10 points. Will give brainliest.
TiliK225 [7]

Answer:

<h2>3.94 kg</h2>

Explanation:

Given,

Force ( f ) = 30 N

Acceleration(a) = 7.6 m/s

Now, Let's find the mass of the ball

Using the Newton's second law of motion:

We get:

force \:  = mass \:  \times acceleration

plug the value

30 \:  = m \:  \times 7.6

Use the commutative property to reorder the terms

30 = 7.6 \: m

Swap the sides of the equation

7.6m = 30

Divide both sides of the equation by 7.6

\frac{7.6 \: m}{7.6}  =  \frac{30}{7.6}

Calculate

m = 3.94 \: kg

Hope this helps..

Best regards!!

7 0
3 years ago
Read 2 more answers
Jason and Guy are throwing watermelons straight up from the ground. (They’re making fruit salad.) Jason throws his watermelon at
NISA [10]

Answer:2t

Explanation:

Given

Jason throwing watermelon at speed v and it spend t time in air

time to reach max height

v_f=u_i+at'

0=v-gt'

t'=\frac{v}{g}

and time to reach bottom is also t'

t=2t'

t=2\frac{v}{g}

For guy throws his watermelon at speed 2v

So total time in air will be

t''=2\frac{2v}{g}

t''=4\frac{v}{g}

t''=2t

5 0
3 years ago
When is thermal equilibrium achieved between two objects?
ratelena [41]

C) When both objects have the same temperature.

<em>Hope this helps!</em>

5 0
3 years ago
Read 2 more answers
A jet airplane is in level flight. The mass of the airplane is m=9010kg. The airplane travels at a constant speed around a circu
Lyrx [107]

Answer:

The magnitude of the lift force L = 92.12 kN

The required angle is ≅ 16.35°

Explanation:

From the given information:

mass of the airplane = 9010 kg

radius of the airplane R = 9.77 mi

period T = 0.129 hours = (0.129 × 3600) secs

= 464.4 secs

The angular speed can be determined by using the expression:

ω = 2π / T

ω = 2 π/ 464.4

ω = 0.01353 rad/sec

The direction \theta = tan^{-1} ( \dfrac{\omega ^2 R}{g})

\theta = tan^{-1} ( \dfrac{0.01353 ^2 \times (9.77\times 1609)}{9.81})

θ = 16.35°

The magnitude of the lift force  L = mg ÷ Cos(θ)

L = (9010 × 9.81) ÷ Cos(16.35)

L = 88388.1  ÷ 0.9596

L = 92109.32 N

L = 92.12 kN

3 0
3 years ago
What is the direction of the magnetic field if an electron moving in the positive x direction experiences a magnetic force in th
Alex787 [66]

Given :

An electron moving in the positive x direction experiences a magnetic force in the positive z direction.

To Find :

The direction of the magnetic field.

Solution :

We know, force is given by :

\vec{F}=q(\vec{v}\times \vec{B)}

Here, q = -e.

\vec{F}=(-e)(\vec{v}\times \vec{B)}\\\\\hat{k}=(-e)(\hat{i}\times \vec{B})

Now, for above condition to satisfy :

\hat{i}\times \vec{B}=-\hat{k}

So, \vec{B}=-\hat{j}

Therefore, direction of magnetic field is negative y direction.

Hence, this is the required solution.

7 0
3 years ago
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