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Vedmedyk [2.9K]
1 year ago
13

Will give brainliest! if 32.0 g of hcl is to be diluted to make a 4.80 m solution, how much water should be added?

Chemistry
1 answer:
nadezda [96]1 year ago
6 0

The required volume of water is 0.18 liters.

<h3>What is molarity?</h3>

Molarity of any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V

Moles of solute will be calculated as:

n = W/M, where

W = given mass of HCl = 32g

M = molar mass of HCl = 36.4g/mol

n = 32 / 36.4 = 0.88 mole

Given molarity of solution = 4.80M

On putting all values in the above equation, we get

V = (0.88) / (36.4) = 0.18 L

Hence required volume of water is 0.18L.

To know more about volume & concentration, visit the below link:

brainly.com/question/26762947

#SPJ1

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2Ag (s) + H2S(s) → Ag2S(s) + H2(g)
Advocard [28]

Answer: Oxidation half: 2Ag\rightarrow 2Ag^++2e^-

Reduction half: 2H^++2e^-\rightarrow H_2

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

2Ag(s)+H_2S(s)\rightarrow Ag_2S(s)+H_2(g)

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Oxidation half: 2Ag\rightarrow 2Ag^++2e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Reduction half: 2H^++2e^-\rightarrow H_2

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2 years ago
Two ways the rate of a reaction be monitored
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Explanation:

https://courses.lumenlearning.com/introchem/chapter/measuring-reaction-rates/#:~:text=If%20a%20reaction%20produces%20a,mass%20of%20the%20reaction%20solution.

This is the site I got it from.  I hope this helps.

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2 years ago
I NEED HELP PLEASE !!!!!
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"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the
ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

Moles of propylene = \frac{43g}{42g/mol}=1.024 mol

1 mole = N_A =6.022\times 10^{23} molecules/ atoms

Units of ethylene = 2.036 mol\times N_A

Units of propylene = 1.024 mol\times N_A

a) Fraction of ethylene units:

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3 years ago
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