Answer:
1. 1.34g
2. 1.19g
3. 0.49g
Explanation:Please see attachment for explanation
Use formula n= number of particles / avogrado constant
n= number of mole
avogrado constant= 6.12x10^-23
you will get 2.042 x 10^52
Answer:
when the school or any institition related to education runs the instution in such a way that the institition dosenot get profit is called educational loss
Explanation:
In the extreme winters , the water inside pipes freeze, on freezing it's(water molecule) density decreases and volume increases and therefore, the ice then expands and pushes the water towards the faucet, causing high pressure buildup in the pipe and after a limit the pipe burst. This is what happened to the family in Ottawa, where winters are chilly.
Answer:
Option B. 0.285m NaCl
Explanation:
To find the molality, first let find the number of mole of NaCl in the solution. This is illustrated below
Molar Mass of NaCl = 58.5 g/mol
Mass of NaCl = 10g
Number of mole of NaCl = Mass of NaCl / molar Mass of NaCl
Number of mole of NaCl = 10/58.5 = 0.1709mol
Mass of water = 600g = 600/1000 = 0.6kg
Molality = mole of solute / mass of solvent
Molality = 0.1709mol/0.6kg
Molality = 0.285mol/Kg
