Answer:
Next, the lb will be canceled at 2.2 lb and the kg would be canceled at 1 kg. You cross, multiply, then. 46 x 1 x 1000 is 46000, only moving to the decimal point. 1 x 2.2 x 1 will stay the same, so you'd have 46000 over 2.2.
Explanation:
kuroo man <3
If this is for chemistry then it's "made up of atoms."
Answer:
Krypton.
Explanation:
By Graham's Law:
Rate 1 / Rate 2 = sqrt M2 / sqrt M1
Molecular Mass for Neon is 20.18
so we have:
38 / 77.5 = sqrt 20.18 / sqrt x where x is the unkown gas.
sqrt x = 9.162
x = 83.94.
This gas is Krypton.
Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
<h3 /><h3>Reaction stoichiometry</h3>
The balanced reaction is:
3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 3 moles
- HNO₃: 8 moles
- Cu(NO₃)₂: 3 moles
- NO: 2 moles
- H₂O: 4 moles
<h3>Amount of moles of NO produced</h3>
It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

<u><em>amount of moles of NO= 6.75 moles</em></u>
In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
Learn more about reaction stoichiometry:
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Answer:
![[CO]=[Cl_2]=0.01436M](https://tex.z-dn.net/?f=%5BCO%5D%3D%5BCl_2%5D%3D0.01436M)
![[COCl_2]=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.00064M)
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:
![K=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Which can be written in terms of x, according to the ICE table:

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:
![[CO]=[Cl_2]=0.01436M](https://tex.z-dn.net/?f=%5BCO%5D%3D%5BCl_2%5D%3D0.01436M)
![[COCl_2]=0.015M-0.01436M=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.015M-0.01436M%3D0.00064M)
Regards!