B,c and f are true,but I doubt about g cause I don't know anything about electron's dimention
<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2>

<h2>_____________________________________</h2><h2>

</h2>
London Dispersion force or Van de waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.
<h2>_____________________________________</h2><h2>

</h2>
Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.
<h2>_____________________________________</h2><h2>

</h2>
It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
First, we should get moles acetic acid = molarity * volume
=0.3 M * 0.5 L
= 0.15 mol
then, we should get moles acetate = molarity * volume
= 0.2 M * 0.5L
= 0.1 mol
then, we have to get moles of OH- which added:
moles OH- = molarity * volume
= 1 M * 0.02L
= 0.02 mol
when the reaction equation is:
CH3COOH + OH- → CH3COO- + H2O
moles acetic acid after adding OH- = (0.15-0.02)
= 0.13M
moles acetate after adding OH- = (0.1 + 0.02)
= 0.12 M
Total volume = 0.5 L + 0.02 L= 0.52 L
∴[acetic acid] = moles acetic acid after adding OH- / total volume
= 0.13mol / 0.52L
= 0.25 M
and [acetate ) = 0.12 mol / 0.52L
= 0.23 M
by using H-H equation we can get PH:
PH = Pka + ㏒[salt/acid]
when we have Ka = 1.8 x 10^-5
∴Pka = -㏒Ka
= -㏒ 1.8 x 10^-5
= 4.7
So by substitution:
∴ PH = 4.7 + ㏒[acetate/acetic acid]
= 4.7 + ㏒(0.23/0.25)
= 4.66
Answer:
Glucose
Explanation:
Glucose, also called dextrose is one of a group of carbohydrates known as simple sugars or monosaccharides. Glucose is derived from the Greek word 'glykys' meaning “sweet”. It has the molecular formula C6H12O6. It is commonly found in fruits and honey and is the major free sugar circulating in the blood of higher animals. It is the source of energy in cell function, and the regulation of its metabolism is of great importance. Molecules of starch, the major energy-reserve of carbohydrate of plants, consist of thousands of linear glucose units. Another major compound composed of glucose is cellulose, which is also linear. Dextrose is the molecule D-glucose.
Glucose is composed of carbon hydrogen and oxygen in a ratio of 1:2:1 as typified by its formula. It is known for its sweet taste. It can be combined with fructose in table sugar.