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hodyreva [135]
3 years ago
13

An object launched from Earth must attain a speed of 7,900 m/s to achieve a low orbit. What happens if the object’s maximum spee

d is less than 7,900 m/s?
Physics
1 answer:
Bingel [31]3 years ago
5 0
It will not achieve a state of low orbit and will not go into space.
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a bus travels 4 km due north and 3 km due west going from bus station a to bus station b. the magnitude of the bus displacement
ladessa [460]

Answer:

5km

Explanation:

Magnitude of displacement is found by getting the resultant. Resultant is same as the bypotenuse hence

R=\sqrt {{x^{2}+y^{2}} where x is the displacement in west direction and y is displacement in North direction. Substituting x with 3km and y with 4 km then

R=\sqrt {{3^{2}+4^{2}}=5km

4 0
3 years ago
The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 rpm. These
alexdok [17]

Answer:

θ  = 6.3 *10³ revolutions

Explanation:

Angular acceleration of the drill

We apply the equations of circular motion uniformly accelerated

ωf= ω₀ + α*t  Formula (1)

Where:  

α : Angular acceleration (rad/s²)  

ω₀ : Initial angular speed ( rad/s)  

ωf : Final angular speed ( rad

t :  time interval (s)

Data

ω₀ = 0

ωf = 350000 rpm = 350000 rev/min

1 rev = 2π rad

1 min= 60 s

ωf = 350000 rev/min =350000*(2π rad/60 s)

ωf = 36651.9 rad/s

t = 2.2 s

We replace data in the formula (2) :

ωf= ω₀ + α*t

36651.9 = 0 + α* (2.2)

α = 36651.9 / (2.2)

α = 17000 rad/s²

Revolutions made by the drill

We apply the equations of circular motion uniformly accelerated

ωf²= ω₀ ²+ 2α*θ Formula (2)

Where:  

θ : Angle that the body has rotated in a given time interval (rad)

We replace data in the formula (2):  

(ωf)²= ω₀²+ 2α*θ

(36651.9)²= (0)²+ 2( 17000 )*θ

θ = (36651.9)²/ (34000 )

θ  = 39510.64 rad = 39510.64 rad* (1 rev/2πrad)

θ  = 6288.31 revolutions

θ  = 6.3 *10³ revolutions

3 0
4 years ago
A raised plaster cover (often called a plaster ring or mud ring) is permitted to increase the maximum number of conductors permi
andreev551 [17]

Answer:

When it is marked with its cubic-inch volume

Explanation:

Because this allows for best and efficient identification

6 0
3 years ago
Why does the hood of a car heat up after the car has been running for a while? A) According to the fourth law of thermodynamics,
Svetlanka [38]

Answer:

C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car.  

Explanation:

A) According to the fourth law of thermodynamics, the temperature of the other parts of the car increases due to the coolant used for the engine.  

B) According to the first law of thermodynamics, the hood of the car heats up using heat from the surroundings in-order to achieve thermal equilibrium with the engine.  

C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car.  

D) According to the third law of thermodynamics, the increase in the velocity of the car changes the entropy of the tires. To balance this change, the temperature of the other parts is increased.

6 0
4 years ago
Read 2 more answers
Bob runs 1800 seconds at an average speed of 1.5 m/sec. How far did he go? 25 Points!!!!
german

Distance= Time×Speed

= 1800×1.5

= 2700 m

I am not sure it's right. the question itself is confusing.

4 0
3 years ago
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