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mash [69]
3 years ago
13

Two toroidal solenoids are wound around the same form so that the magnetic field of one passes through the turns of the other. S

olenoid 1 has 690 turns and solenoid 2 has 450 turns. When the current in solenoid 1 is 6.60 A, the average flux through each turn of solenoid 2 is 3.50×10-2 Wb.
A: What is the mutual inductance of the pair of solenoids?

B: When the current in solenoid 2 is 2.60 A, what is the average flux through each turn of solenoid 1?
Physics
1 answer:
dedylja [7]3 years ago
8 0

The concept that we need here to give a proper solution is mutual inductance.

The mutual inductance  is given by the expression

M=\frac{N\Phi}{I}

Where,

I = current

N = Number of turns

\Phi =Flux through the solenoid.

Part A) Then we have in our values that,

I=6.6A

\Phi= 3.50*10^{-2}Wb

N=450

Replacing in the equation,

M = \frac{450*350*10^{-2}}{6.60}

M = 2.39H

Part B) Here is required the Flux, then using the same expression we have that

\Phi = \frac{IM'}{N}

We conserve the same value for the Inductance but now we have a current of 2.6, then

\Phi = \frac{2.6*2.39}{690}

\Phi = 9*10^{-3}Wb

Therefore the flux in Solenoid 1 is 9*10^{-3}Wb

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Answer:

option D

Explanation:

given,

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hall voltage =V_h =\dfrac{i\ B}{n\ e\ L}

n = \dfrac{i\ B}{V\ e\ L}

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n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D

7 0
3 years ago
Yamin is running 50 feet of No. 14 wire (with a cross section of 4,110 cmils) to a load that draws current of 11 amps. What appr
castortr0y [4]

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now if wire is of length 50 feet only then the resistance is given as

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V = 1.4 Volts

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Answer:

Heat capacity, Q = 2090 Joules.

Explanation:

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To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mct

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Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature of an object.

Substituting into the formula, we have;

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2 years ago
A plane starting from rest accelerates at 3m/s2 for 25s. Calculate the increase in velocity after:
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Time not needed now

Case-1:-

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\\ \rm\hookrightarrow v=u+at

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Case-3:-

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\\ \rm\hookrightarrow v=0+3(25)

\\ \rm\hookrightarrow v=75m/s

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