Density = 7.36 grams ÷ (2 cm × 2 cm × 2cm) = 0.92 g/cm^3
Answer:
H vaporization = 100.0788 kJ/mol
Explanation:
Use clausius clapyron's adaptation for the calculation of Hvap as:
Where,
P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.
R is the gas constant.
T₂ = 823°C
T₁ = 633°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So, the temperature,
T₂ = (823 + 273.15) K = 1096.15 K
T₁ = (633 + 273.15) K = 906.15 K
P₂ = 400.0 torr , P₁ = 40.0 torr
R = 8.314 J/K.mol
Applying in the formula to calculate heat of vaporization as:
Solving for heat of vaporization, we get:
H vaporization = 100078.823 J/mol
Also, 1 J = 10⁻³ kJ
So,
<u>H vaporization = 100.0788 kJ/mol</u>
Answer:
Explanation:
Suppose mass of block 1 is and of block 2
For original system
natural frequency of oscillation is given by
Maximum kinetic Energy is equal to total Energy of the system
where k=spring constant
A=maximum amplitude
Now Block B is Placed at block 1 at maximum amplitude such that A=A'
i.e. new amplitude=old amplitude
Maximum kinetic energy of combined system is
as the total energy is independent of mass therefore maximum kinetic energy will remain same
Answer:
The correct answer is no.
Explanation:
The temperature of a person changes depending on their age, the physical activity they are doing and until the time of day.
There is an established average temperature that is 98.6 ° F (37 ° C) as a healthy temperature.
If the temperature exceeds 100.4 ° F (38 ° C) it means that you may be ill or have an infection.
The difference in temperature by age is very minimal, but it is still a difference. Let's see:
- Babies and children: from 97.9 ° F (36.6 ° C) to 99 ° F (37.2 ° C).
- Adults: from 97 ° F (36.1 ° C) to 99 ° F (37.2 ° C).
- Adults over age 65: 98.6 ° F (36.2 ° C).
Answer:
5.76 cm³
Explanation:
Using the equation for volume expansivity,
V = V₀ + V₀γΔθ) where V₀ = volume of cube = volume of mercury = 400 cm³, γ = cubic expansivity of mercury = 18 × 10⁻⁵ /K and Δθ temperature change = θ₂ - θ₁ where θ₁ = 0 °C and θ₂ = 80°C. So, Δθ = 80°C - 0°C = 80°C = 80 K
Now, the volume change, ΔV = V - V₀ = V₀γΔθ.
So, substituting the values of the variables into the equation, we have
ΔV = V₀γΔθ
= 400 cm³ × 18 × 10⁻⁵ /K × 80 K
= 5.76 cm³
So the mercury will overflow by 5.76 cm³.