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2 years ago

For the following element, predict the most likely oxidation number (charge) for its corresponding ion.

Chemistry

1 answer:

Morgarella [4.7K]2 years ago

5 0

<h2>Answer: D. P-3</h2>

<h3>Explanation:</h3>

The most likely ion of Phosphorous is P³⁻ (group 15) since gaining three electrons is the most energetically favorable way for it to follow the octet rule.

Because the charge on ions is equivalent to their oxidation state, then -3 is the most likely oxidation number of Phosphorous.

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What minimum volume of 0.200 m potassium iodide solution is required to completely precipitate all of the lead in 195.0 ml of a

lbvjy [14]

First, we write the reaction equation:

2KI + PbNO₃ → K₂NO₃ + PbI₂
The molar ratio of KI to PbNO₃ is 2 : 1
Moles of PbNO₃ present:
Moles = concentration (M) x volume (dm³)
= 0.194 x 0.195
= 0.038
Moles of KI required = 2 x 0.038 = 0.076 moles
concentration = moles / volume
volume = moles / concentration
= 0.076 / 0.2
= 0.38 L = 380 ml

7 0

3 years ago

You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q

Flauer [41]

Answer:

6,78 mL of 12,0 wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = $10^{-7,20}$ , thus,

Thus, you need to add:

[H⁺] = $10^{-7,2} -10^{-8,0}$ = 5,31x10⁻⁸ M

The total volume of the pool is:

9,00 m × 15,0 m ×2,50 m = 337,5 m³ ≡ 337500 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 337500 L = 1,792x10⁻² moles of H⁺

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,792x10⁻² moles of H⁺ × $\frac{1H_{2}SO_4 mol}{2H^{+} mol}$ = 8,96x10⁻³ moles of H₂SO₄

These moles comes from:

8,96x10⁻³ moles of H₂SO₄ × $\frac{98,1 g}{1 mol}$ × $\frac{100 gSolution}{12 gH_{2}SO_4 }$ × $\frac{1 mL}{1,080 g}$ =

6,78 mL of 12,0wt% H₂SO₄

I hope it helps!

8 0

3 years ago

See the questions on the sheet

Sergio [31]

Answer:

Question 1. Nonpolar covalent

Question 2. The fluorine atom is able to attract the shared electrons more strongly than a hydrogen atom

Question 3. True

Explanation:

Question 1

First of all, oxygen is a molecular compound, as it consists of non-metal atoms only (oxygen). This means we wouldn't expect to have any ionic bonding in it, as it doesn't contain a metal ion. A molecular compound has covalent bonding.

Whenever a diatomic molecule contains the same two atoms bonded by a bond, we expect to have a non-polar bond. This is due to the fact that the two atoms are identical and have the same values of electronegativity, meaning the difference in their electronegativity values is 0 and we have no net polarity within the bond.

For a bond between two different atoms, the molecule would be polar, as one atom would have a greater electronegativity (electron withdrawing force) compared to the other atom.

Question 2

Based on the principles of polarity, whenever we have a diatomic molecule, it's only non-polar when the two atoms are the same. In case of HF, we have two different atoms: hydrogen and fluorine. Since the two atoms are not identical, the molecule would be polar overall, as fluorine is more electronegative than hydrogen. Simply speaking, it means that fluorine attracts the shared electrons within the H-F bond stronger than hydrogen does. This makes a difference in electronegativity values between H and F non-zero and an overall polar bond.

Question 3

We may recall the Coulombic force equation. It states that the attraction force is directly proportional to the charge and inversely proportional to the square of a distance between the two charges.

A bond formed between two atoms or ions is the closest distance the two species can approach each other. Intermolecular forces, in contrast, are the forces that atoms experience within a distance greater than the bond length. We may conclude that for a greater distance, the Coulombic force is lower and, hence, the strength of intermolecular forces are significantly lower compared to covalent or ionic bonds.

7 0

3 years ago

What is an example of an organ A.pancreas B.blood C.insulin D.knee

marissa [1.9K]

Answer: pancreas

Explanation:

4 0

3 years ago

Read 2 more answers

Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L

const2013 [10]

Answer:

The answer is 1.15m.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.

We can find the number of H2SO4 moles by using its molarity

C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288

Since water has a density of 1.00kgL, the mass of solvent is

m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg

Therefore, molality is

m=nmass.solvent=0.288moles0.250kg=1.15m

4 0

3 years ago

Read 2 more answers