Can you include the pome pls
D = m / V
D = 2790 g / 205 mL
D = 13.60 g/mL
Answer:
Concentration of nitrate in the new solution = 0.007 M
Explanation:
Given:
Concentration nitrate solution = 0.070 m
Volume of aliquote of the nitrate solution is add = 10.0 ml
Total volume = 100 ml
Find:
Concentration of nitrate in the new solution
Computation:
Number of M. mole = 0.070 m x 10.0 ml
Number of M. mole = 0.7 m-moles
Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml
Concentration of nitrate in the new solution = 0.007 M
Answer:
Solid Rocky Dense
Please Mark Brainliest If This Helped!
Iron(III) sulfide is the name of the compound written using the Stock system. In the Stock system (named for Alfred Stock) a Roman numeral is used to indicate the oxidation number of the metal. Roman numerals are used in the names of compounds where the metal exhibits two or more oxidation states.
The sum of the oxidation states of a compound must always be zero. The oxidation state of sulfide is -2, and the oxidation state of sulfur, we are told by (III) is +3. You can either use the "criss-cross" trick to get the subscripts where the oxidation number of Fe becomes the subscript of S, and the oxidation number of S becomes the subscript of Fe...
+3-2
.FeS --> Fe2S3 .
Am 100% Sure The Best Answer..
