Answer:
Na2B4O7 + H2SO4 + 5H2O → 4H3BO3 + Na2SO4
Explanation:
The unbalanced equation is given as;
Na2B4O7 + H2SO4(aq) + H2O → H3BO3(s) + Na2SO4(aq)
Balancing the equation of the reaction involves making sure the number of moles of elements in the reactants to be equal to the number of moles of the element of the products.
The balanced equation is given as;
Na2B4O7 + H2SO4 + 5H2O → 4H3BO3 + Na2SO4
One month after the full moon is another full moon.
Hope this helps :)
Answer:
40.72g of sulfuric acid are needed
Explanation:
When sulfuric acid, H₂SO₄, is neutralized by lead (IV) hydroxide, Pb(OH)₄, Lead (IV) sulfate, Pb(SO₄)₂ and water as follows:
2 H₂SO₄ + Pb(OH)₄ → Pb(SO₄)₂ + 4H₂O
To solve this question we must find the moles of 57.18g of Pb(SO₄)₂. As 2 moles of H₂SO₄ produce 1mol Pb(SO₄)₂ we can find the moles of H₂SO₄ and its mass as follows:
<em>Moles Pb(SO₄)₂ -Molar mass: 275.23 g/mol-</em>
57.18g * (1mol / 275.23g) = 0.2078 moles Pb(SO₄)₂
<em>Moles H₂SO₄:</em>
0.2078 moles Pb(SO₄)₂ * (2mol H₂SO₄ / 1mol Pb(SO₄)₂) = 0.4155 moles H₂SO₄
<em>Mass H₂SO₄ -Molar mass: 98g/mol-</em>
0.4155 moles H₂SO₄ * (98g / mol) =
<h3>40.72g of sulfuric acid are needed</h3>
Answer:
High Performance Computing
hope it helps
The answer is the first one 6,456 miles