Last lesson we calculated that propane has an energy of combustion of 2220 kilojoules per mole while hydrogen gas (rocket fuel)
has an energy of combustion of 286 kilojoules per mole. However, hydrogen gas has a much higher energy of combustion per gram than propane. Why is this? 
1 answer:
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Given :
Moles of Na : 1.06
Moles of C : 0.528
Moles of O : 1.59
To Find :
The empirical formula of the compound.
Solution :
Dividing moles of each atom with the smallest one i.e 0.528 .
So,
Na : 1.06/0.528 = 2.007 ≈ 2
C : 0.528/0.528 = 1
O : 1.59/0.528 = 3.011 ≈ 3
Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.
So, empirical formula is .
Hence, this is the required solution.